Do something like this >>> import os >>> for root, subFolders, files in os.walk(‘/tmp’): … for f in files: … if len(f) < 5: continue … newf = f[:-5]+f[-5].lower()+f[-4:] … print “changing”,f,”to”,newf … but looks like you want character before extension instead of 5 char? in that case why not just split the extension from … Read more
I am writing a program which adds numbers inputed by the user and then outputting the total. With the total how can i output all the inputed numbers solved I am writing a program which adds numbers inputed by the user and then outputting the total. With the total how can i output all the … Read more
It is minimal example which create database with two elements and later it uses data from database to fill Treeview You have to use create() only once. import tkinter as tk from tkinter import ttk import sqlite3 def create(con): cur = con.cursor() cur.execute(”’CREATE TABLE IF NOT EXISTS user ( id INTEGER PRIMARY KEY, name TEXT … Read more
You can use sympy, Python’s symbolic math library. from sympy import solve from sympy.abc import C print(solve(1298 + 74.86 * C + 1.283 * C ** 2 – .0078 * C ** 3 – .0006 * C ** 4)) # result: [-28.2719434096994, 62.3383358961427, -23.5331962432216 – 25.9550273611766*I, -23.5331962432216 + 25.9550273611766*I] 0 solved How to solve this … Read more
i solved it: number_of_laptops = int(input()) list_of_prices = [] list_of_qualities = [] for i in range(0,number_of_laptops): inp = input() numbers = [] numbers = [int(s) for s in inp.split() if s.isdigit()] list_of_prices.append(numbers[0]) list_of_qualities.append(numbers[1]) def find_better_lp(number_of_laptops): if number_of_laptops == 0: return print(“empty list”) for i in range(0,number_of_laptops): for j in range(0,number_of_laptops): if((list_of_prices[i] <= list_of_prices[j]) and i … Read more
There are certain cases where the voice client can get into a bad state and think that you’re not connected when you are. Try using the force argument for VoiceClient.disconnect and setting it to True when you disconnect. 1 solved Can’t make Discord bot leave the voice channel in Python
When I run your code I get the following exception: TypeError: __init__() takes exactly 3 arguments (1 given) You have to pass x and y arguments to the constructor or define default values: Arguments to the constructor: object1 = a(“name”, “family”) Default values: class a(object): def __init__(self, x=””, y=””): … 12 solved What is the … Read more
Use Json library: To save dict into file with open(“your_file”) as f: f.write(json.dumps(your_dict)) To load dict from file with open(“your_file”) as f: d = json.load(f) 0 solved I can not transform a file to a dictionary in python [duplicate]
Your tabs and spaces must be getting mixed up. Set you editor to 4 spaces for a tab. You can also turn on whitespace indicator on the editor, which can help resolving the indentation errors. solved Python Indentation Error when there is no indent error
as far as the error is concerned print(list1[random].randint(1,length)) should be changed to print(list1[random.randint(1,length)]) 2 solved How do I use permutation to find all possible words from an input? [closed]
Order of elements The PEP 202 is not very… comprehensive, but you can found some information in the Python Language Reference: The comprehension consists of a single expression followed by at least one for clause and zero or more for or if clauses. In this case, the elements of the new container are those that … Read more
From your description, I think you want something like this: >>> a = 1 >>> b = 2 >>> c = [3, 4, 5] >>> d = [6, 7, 8] >>> for cx, dx in zip(c, d): for item in (a, b, cx, dx): print(item) print(“—“) 1 2 3 6 — 1 2 4 7 … Read more
Regular expression functions in Python return None when the regular expression does not match the given string. So in your case, match is None, so calling match.groupdict() is trying to call a method on nothing. You should check for match first, and then you also don’t need to catch any exception when accessing groupdict(): match … Read more
You need to break up the rows and convert each value to an integer. At the moment you are looking for the presence of the string “3” which is why strings like “2;13” pass the test. Try something like this: list_6 = [“4;99”, “3;4;8;9;14;18”, “2;3;8;12;18”, “2;3;11;18”, “2;3;8;18”, “2;3;4;5;6;7;8;9;11;12;15;16;17;18”, “2;3;4;8;9;10;11;13;18”, “1;3;4;5;6;7;13;16;17”, “2;3;4;5;6;7;8;9;11;12;14;15;18”, “3;11;18”, “2;3;5;8;9;11;12;13;15;16;17;18”, “2;5;11;18”, “1;2;3;4;5;8;9;11;17;18”, … Read more
If you dont want to use list comprehension: my_list=[] for i in range(5): n=int(input(“Enter and integer number:”)) my_list.append(n) print(my_list) for index, i in enumerate(my_list): if i%5==0: my_list[index] = i + 5 print (my_list) 1 solved Create list from user input and modify some elements