You assigned a string to the operator name: operator = randomOp[0] You are now masking the operator module. Don’t re-use names like that, because the next iteration of your for loop operator.add now tries to look up the add attribute on that string (so one of ‘+’, ‘-‘ or ‘*’, whatever the first iteration picked … Read more
This answer is assuredly overkill for your simple line selection problem, but it illustrates a nice property of Python: Often a very generalized pattern of behavior or processing can be very generally stated in a way that goes well beyond the original use case. And instead of creating a one-time tool, you can create very … Read more
If your second dataframe in your upper screenshot is called df, this should do: df.set_index(‘Name’).stack().reset_index(level=0) 2 solved Panda Data Manipulation
I have a txt file with a list of numbers in a column. I want to see what numbers are missing and display what numbers are missing solved I have a txt file with a list of numbers in a column. I want to see what numbers are missing and display what numbers are missing
I suspect what you are talking about is a quine. a Simple quine in python would be s = r”print ‘s = r\”{0}\”‘.format(s), ‘\n’, s” print ‘s = r\”{0}\”‘.format(s), ‘\n’, s solved Source Code is the output in Python [closed]
Since ipython has already been discounted, I’m not sure this answer will be better. But I will tell you the two things that I do. I drop into the debugger at the point where I want to “try out” something, so the code will run up to that point, and then drop me into the … Read more
The built-in function you seem to be looking for is str.translate: S.translate(table [,deletechars]) -> string Return a copy of the string S, where all characters occurring in the optional argument deletechars are removed, and the remaining characters have been mapped through the given translation table, which must be a string of length 256 or None. … Read more
Objects in python have reference count which basically means the amount of places an object exist in. Using del removes one reference to the object (it does not force delete it). __del__ is then called when 0 references are left. You may create a new reference to the object and this way prevent it’s deletion … Read more
Roll-your-own parser code is silly. Python has batteries included for this: import datetime repeat = True datestr = raw_input(‘Enter a date in the format MM/DD/YYYY’) while repeat: try: # Parse to datetime, then convert to date since that’s all you use date = datetime.datetime.strptime(datestr, ‘%m/%d/%Y’).date() except ValueError: pass # Handle bad dates in common code … Read more
To just add a count you could keep a set of itertools.count objects in a defaultdict: from itertools import count from collections import defaultdict counters = defaultdict(lambda: count(1)) result = [(n, next(counters[n])) for n in inputlist] but this would add counts to all elements in your list: >>> from itertools import count >>> from collections … Read more
You forgot to call the conversion function for some parameter in your function. I tested and corrected your code, call it this way: is_verified = verified( convert(data[‘k_signer’]), data[‘d_pk’], convert(data[‘d_signer’]), data[‘sig’], convert(data[‘addr’]), convert(data[‘seed’]), convert(data[‘data’]) ) solved How can i fix concatenate tuple (not “list”) to tuple
this is b/c the while True does not end unless you use the keyword break wich breaks outside the loop and continues the code. the while True never ends the while loop while (condition): #code never ends until the condition is False, witch would never be true for the True condition. do your code should … Read more
The python function split() by default splits your text on spaces. You can add separator inside, for example: task.split(‘,’) which means this function is going to split your text in list by commas. See more examples on w3schools. solved how to print each value of list on next line in python [closed]
Just split by a newline and get the first element: test_str = “# <init> (Lorg/cyanogenmod/audiofx/ActivityMusic;)V\n , 0 iput-object v1, v0, Lorg/cyanogenmod/audiofx/ActivityMusic$11;->this$0 Lorg/cyanogenmod/audiofx/ActivityMusic;\n , 4 invoke-direct v0, Ljava/lang/Object;-><init>()V\n , a return-void ” print(test_str.split(‘\n’)[0]) See demo Output: # <init> (Lorg/cyanogenmod/audiofx/ActivityMusic;)V. If it is not the first line: A non-regex way: test_str = “some string\n# <init> (Lorg/cyanogenmod/audiofx/ActivityMusic;)V\n , … Read more
Pointing out the mistakes/unnecessary lines in your code: The line split = strings.split().upper() is erroneous and at the same time unnecessary as you are mistakenly using strings (list) instead of string (string literal). Also, you can use len(string) directly instead of splitting the string into a list and finding the length of list. result.append(char * … Read more