The python function split() by default splits your text on spaces. You can add separator inside, for example: task.split(‘,’) which means this function is going to split your text in list by commas. See more examples on w3schools. solved how to print each value of list on next line in python [closed]
The Main approach for checking elements of a list in a string is : s=””‘<a href=”https://ertfwetwer” target=”_blank”>[Nerve Center]</a>”’ my_list=[‘href’,’a’] def checker(mylist, my_string) new = list() for i in mylist: if i in my_string: # if elements is in string (you can check only special elements ) print i ,’is in string’ new.append(i) #storing result to … Read more
just use count(), $array = array(1,3,2,4,6); $a=count($array); echo $a; solved PHP : Counting how many element in an array [closed]
Yes, just copy xpath of element using browser dev tools (F12) 1 solved How can I select this span class element using Selenium 3?
Updated: Based on inputs from user, the requirement can easily be achieved using the plugin Swiper, Please find below an example. JSFiddle Old Answer: I have tried what you asked, it looks uh UGLY, first version is having elements side by side. I have used float:left and margin-left instead of left. JSFiddle The second version … Read more
Try :eq() and .after() $(‘table tr:eq(3)’).after(‘<tr><td>5</td></tr>’); fiddle Demo or .insertAfter() $(‘<tr><td>5</td></tr>’).insertAfter(‘table tr:eq(3)’); fiddle Demo 2 solved How do I add a table row to a table after the forth using Javascript and or jQuery? [closed]
You can do something like this : input_num = 123 list1 = [0, 1, 2, 3, 4] # if list1 is not dervied from input number list2 = [“0”, “hello”, “my”, “name”, “is”, “Daniel”] print(‘ ‘.join([list2[list1.index(int(ind))] for ind in str(input_num)])) This will result in : hello my name Also, i would suggest you to look … Read more
This data structure is very difficult to deal with. I would consider if this is the best way to store this data. Maybe an array of structs that represent your data? The confusing part is your variable is named array, but it is really declared as a Dictionary literal. So to access the item with … Read more
arr[-1] gives you the last element of arr, arr[-2] the second-to-last element and so on. arr[2, 3] gives you from the element at index 2, three elements of arr arr[2..3] gives you from the element at index 2 to the element at index 3 2 solved Accessing ruby elements