Please make sure you do more research next time when you post another question. This object loop, as you mentioned, will not work on your data as it as array of objects and not an object. So, will have to loop through as an array. Here is what you can use: var obj = [ … Read more
The problem is that the value you are attempting to assign to list1 is a Set, but the list1 var is of type List. The compiler error explains this as best it can, but perhaps the error message is a bit obscure because the right hand side of the assignment could take many types (“polymorphic … Read more
data.map(function(d){ var id = +(d.test.substring(3)); return { value : “ALP”, id: id } }); solved Array to object process with underscore library
The toString() method of the Point class should look like: public String toString() { return “(” + x + “,” + y + “)”; } The toString() method of the Line class should look like (supposing you have two members of type Point in the class Line): public String toString() { return “(” + point_A.getX() … Read more
Use filter and map, with a Set to remove the repeated values: var employee=[{“firstName”:”Zahir”,”lastName”:”Alam”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Amith”,”lastName”:”Manniken”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Sourasis”,”lastName”:”Roy”,”Age”:28,”Company”:”Switchme”,”Role”:”CTO”},{“firstName”:”Aditya”,”lastName”:”Mishra”,”Age”:29,”Company”:”Switchme”,”Department”:”Tech”,”Role”:”CEO”},{“firstName”:”Priti”,”lastName”:”Lata”,”Age”:24,”Company”:”Switchme”,”Role”:”HR”},{“firstName”:”Sumita”,”lastName”:”Nath”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Tarini”,”lastName”:”Khanna”,”Age”:22,”Company”:”Switchme”,”Role”:”Content Writer”},{“firstName”:”Abhisek”,”lastName”:”Soni”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Ankit”,”lastName”:”Pump”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Pogo”,”lastName”:”Laal”,”Age”:23,”Company”:”Switchme”,”Role”:”Designer”},{“firstName”:”Sabina”,”lastName”:”Sekh”,”Age”:28,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Sanjay”,”lastName”:”Poudal”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”,”Head”:{“Id”:10,”Name”:”Sabina Sekh”}}]; var repeated = […new Set(employee.map(({ Department }) => Department).filter(Boolean))]; $(“div.all”).text(repeated.join(“, “)); <script src=”https://code.jquery.com/jquery-3.3.1.js”></script> <h3>2. List out all department name </h3> <div class=”all”></div> 7 solved I want to print only the repeated values … Read more
You can’t sort properties in an object. Copy the data into an array and sort it. Example: var arr = []; $.each(data, function(key, value){ arr.push({ id: key, data: value }); }); arr.sort(function(x,y){ var xn = x.data.userStatuINT; var yn = y.data.userStatuINT; return xn == yn ? 0 : xn < yn ? -1 : 1; }); … Read more
you can call a void method like any other method, except that you don’t have to do anything with the return value because there isn’t one. case 2: listBasket(basket); break; for your third case, you have to pass in both a double and an ArrayList if you want to pass 0 as your double, than … Read more
If I understand the problem correctly, you have 6 Publication objects, and you are only seeing the values of the most recently created one. That would likely be caused because you have static class variables instead of instance variables. For example class A { static int x; // class variable int y; // instance variable … Read more
Modifying answer now that I understand you want the resource identifier of your views: Resources res = getResources(); for (int i = 0; i < ListOfView.size(); i++){ int id = ListOfView.get(i).getId(); try { Log.i(“View “, res.getResourceName(id)); } catch (Resources.NotFoundException e) { Log.i(“Unknown id ” + id); } } 5 solved Android : How To convert … Read more
You can proceed like this: var products = {a:”b”, c:”d”, e:”f”}; var arrList = []; for(var key in products) { // iterates over products key (e.g: a,c,e) arrList.push([key, products[key]]); }; solved Javascript object in array
var array1 = [“column1”, “column2”, “column3”] var array2 = [“infor1”, “infor2”, “infor3”] var obj = {}; array1.forEach(function(y, z) { obj[y] = array2[z]; }); console.log(obj) 0 solved How to set array to object keys javascript [duplicate]
Something like this might work for you: var i; var k; for(i = 0; i < existingArray.length; i++){ var count = 2; for(k = 0; k < existingArray.length; k ++){ if(i != k && existingArray[i].content.host.name === existingArray[k].content.host.name){ existingArray[k].content.host.name += ‘_’ + count; count++; } } } 3 solved How to modify an array of objects … Read more
We can use map, filter reduce for this, it’s slightly tricky but the same principle applies: const data = { periods: [ { decisions: [ { bank: { name: “Team1” }, bSPositionDecisions: [ { totalInputRate: 1.0, positionValue: 12, balanceSheetPosition: { name: “asset_bc_lombard_a_onsight”, category: “LOMBARD_LOANS”, type: “ASSET” } }, { totalInputRate: 2.0, positionValue: 10, balanceSheetPosition: { … Read more
Change JSONArray list = new JSONArray(Jo_result.getString(“result”)); To JSONObject list = new JSONObject(Jo_result.getString(“result”)); Your string is contained between {} which makes it an object. Keep in mind this {} = Json Object [] = Json Array UPDATE When you do this JSONObject resultsObject = list.getJSONObject(i); it’s expecting another object within the main object, for example : … Read more
thanks to all…..the thing which i dont know was – during a function call if i want to pass an array(arr[]) as argument then i just need to pass its name(arr) as argument not the square brackets([]) along with it. Here is my new optimized error free code which has been submitted successfully. import java.util.*; … Read more