You have a lot of error in your code : First Don’t ever name your variables with Upper letter in beginning, java use camelCase Second Don’t declare your variable with private public in your method. private ArrayList<Object> List = new ArrayList<Object>(); Third You can’t declare a method inside another method you have to close the … Read more
Instead of Workday.ToString(), you might try to print Workday ? “yes” : “no” , which is a short if else statement which prints “yes” when Workday is True, “no” otherwise. Hope this helps! solved Changing bool value to word using ToString method [duplicate]
First of all, toString method comes from object class, don’t try to make multiple of those methods or anything like that, have everything in one method. As to your problem, you can make a variable String description for your class, and initialize it in constructor and then in toString just return that variable. You can … Read more
You can override toString() to get the desired description of the instances/classes. Code: class ComplexNum { int a,b; ComplexNum(int a , int b) { this.a = a; this.b = b; } @Override public String toString() { return a + “+” + b + “i”; } public static void main(String[] args) { ComplexNum c = new … Read more
Looks like you have a semi-colon where a left curly brace should be to open the function scope solved std::stringstream object unrecognized in std::to_string replacement function [closed]
indexOf expects an Object. get gets the item at the specified index previousUrl = historyArray.get(arraySizelink); 2 solved string variable to index of String array ??? JAVA
It seems as if the reason you’re getting an error is because the userReadables is initially set to a null string. in the catch, you have catch(Exception e) { userReadables = null; } and since the userReadables is already null, it’s calling the Exception before it does anything else. Make it something related to the … Read more
All your Parent instances have the same list of children, since you construct a single ArrayList and use it as the children of all three Person. So you have a recursive data structure. Create a different list for each person. solved java.lang.StackOverflowError when trying to add the same instance of list multiple times
Just construct the string step by step in a StringBuilder: @Override public String toString() { StringBuilder sb = new StringBuilder(a).append(” = “); if (b > 1 || b < -1) { sb.append(b); } else if (b == -1) { sb.append(‘-‘); } if (b != 0) { sb.append(‘x ‘); if (c > 0) { sb.append(‘+’); } … Read more
The toString() method of the Point class should look like: public String toString() { return “(” + x + “,” + y + “)”; } The toString() method of the Line class should look like (supposing you have two members of type Point in the class Line): public String toString() { return “(” + point_A.getX() … Read more
You are calling toString() on ComputableLiveData, you have to call toString() on myEntities which will in turn call toString() on the individual elements which are MyEntity. myViewModel.getAllData().observe( this, new Observer<List<MyEntity>>() { @Override public void onChanged(@Nullable List<MyEntity> myEntities) { Log.d(“TAG: “, “DATA CHANGED! ” + myEntities.toString()); } }); 1 solved How to override `toString()` properly to … Read more