You absolutely may call a function within another function in Python, so long as the callee is in the scope of the caller. Check out this question and answer: Short Description of the Scoping Rules? The short of it: inside a function, you can call functions in the global scope, the function scope, or, if … Read more
You just need to see the pattern and replicate it in your code. Here is one way to solve this, which can also be used to produce larger matricies (set the max variable to a different value): public class main{ public static void main(String[] args){ int max = 5; for(int i = 1; i < … Read more
I’m not sure that I really understand your description of what you are doing, but this stands out: this.containers.put(this.currentHashMapKey, tempHashMap); // … tempHashMap.clear(); When you call clear(), you remove all entries from tempHashMap. Since this is the map object that you added as a value in the containers map, you are clearing it there as … Read more
After a few tries, I think I got what I was looking for. body { background: skyblue; } a { text-decoration: none; } .wrapper { margin: 2%; } .articles { display: -webkit-box; display: -ms-flexbox; display: flex; -ms-flex-wrap: wrap; flex-wrap: wrap; } .article-card { background-color: #FFF; box-shadow: 0 4px 4px -4px rg; } .article-card–big { width: … Read more
I think you need to re-query res2 inside the outer loop, or at least reset the pointer. The second time through the outer loop you have nothing left in res2, since you’ve already reached the end In addition, with would be a lot more efficient if you setup the res2 query inside the outer loop … Read more
As explained in previous answer: StringBuilder buf = new StringBuilder(); for (int i = 1; i <= 5; i++) { buf.append(i); for (int j = 1; j <= i; j++) { System.out.println(buf); } } solved Triangular number pyramid in java [closed]
In your outer while loop you need this: overtime = 0; if (hoursWorked>8) overtime = (hoursWorked-8)*(rateOfPay*1.5) – (hoursWorked-8)*rateOfPay; // Calculate OVERTIME HOURS sets the overtime to zero for each iteration, and you’ll have to subtract the normal rate for overtime hours (otherwise you add them twice) and then you’ll have to add the overtime to … Read more
Following your example (Image in your question), you can create an Angular Pipe import { PipeTransform, Pipe } from ‘@angular/core’; @Pipe({name: ‘ObjKeys’}) export class KeysPipe implements PipeTransform { transform(value, args:string[]) : any { return Object.keys(value); } } Imagine this variable following your structure let object = { “RAW”: { “ETH”: { “USD”: { “TYPE”: 5 … Read more
var purchaseValue = 7000; var children = 10; var discount = 0; if(purchaseValue >= 5000){ if(children > 4){ discount = 22; } else if(children > 7){ discount = 30; } } else if(purchaseValue <= 2500){ discount = 10; } var amount = (discount/100) * purchaseValue; 4 solved Using nested if statements ( Help ) [closed]
I may have been massively over complicating things here, this appears to do what I want (ignoring the insertion of completely new markets / selection_id’s for now): new_order_list = [] for x in updated_orders: for y in x[‘Live_orders’]: orders_to_update = {} orders_to_update.update({‘Market_id’: x[‘Market_id’], ‘Selection_id’: y[‘selection_id’], ‘live_orders’: y[‘live_orders’]}) new_order_list.append(orders_to_update) for z in new_order_list: for a in … Read more
You should debug your code by yourself. void stack::push(int *dat) { ch::LinkList* newNode = new ch::LinkList; newNode->initialize(dat,ptr); ptr->head = newNode; } void stack::ch::LinkList::initialize(int *dat, ch *nxt){ data = dat; if(nxt->head) next = nxt->head; else next = 0; } Note that: ptr is nullptr,so nxt is a nullptr too. So you crash… make ptr not null, … Read more
I just looked at your code, you are using spaces and lines 23, 33, 172 should all be spaces instead of tabs. Lines 69-118 should all be indented with spaces. Ok, so your comments on the return statements were messing things up, this code compile fine. Also you didn’t initialize middleName to anything so I … Read more
Nested for loops like that are used when you have pseudo code like this: Do the following x times: Do the following y times: some stuff Do the following z times: some stuff In your specific case, the size of the pyramid is dynamic and is stored in a variable called size. To print a … Read more
I think you need empty list so you can append the numbers to that i.e FirstNumbers = [1, 2, 3] SecondNumbers = [4, 5, 6] ThirdNumbers = [7, 8, 9] NestedNumbers = [FirstNumbers, SecondNumbers, ThirdNumbers] m = [] for i in range(0, 3): k = [] for each_number in NestedNumbers: k.append(each_number[i]) m.append(k) Output m : … Read more
Do you want something like this? const biscuitsPerCat = (cats, biscuits) => { const share = Math.floor(biscuits / cats.length) const cutoff = biscuits – cats.length * share return cats.reduce((res, cat, idx) => ({…res, [cat]: idx < cutoff ? share + 1 : share}), {}) } console.log(biscuitsPerCat([“Andy”, “Bandy”, “Candy”, “Dandy”], 14)) … which you could then … Read more