[ad_1] The list comprehension at the heart of this function is building up an implicit list that ultimately gets returned. We can unwind the function, remove the comprehension, and use an explicit list: def combine(n, k): “”” Given two integers n and k, return all possible combinations of k numbers out of 1 … n. … Read more
[ad_1] given that your data frame is named veryVeryVERYLargeDF lapply(colnames(veryVeryVERYLargeDF)[2:ncol(veryVeryVERYLargeDF)], function(nameOFColumnInveryVeryVERYLargeDF) cbind(veryVeryVERYLargeDF$ID, veryVeryVERYLargeDF[,nameOFColumnInveryVeryVERYLargeDF])) that will give you a list of somewhatSmallerDFs, where each somewhatSmallerDF is simply the ID column from veryVeryVERYLargeDF and one of the other columns from veryVeryVERYLargeDF 2 [ad_2] solved How to create multiple data frames from a huge data frame using a … Read more
[ad_1] You want to create an array with a size of zero which is not allowed. You also can´t declare an array with a variable size so you have to use malloc or something else. #include <stdio.h> #include <stdlib.h> int main() { printf(“HOW MANY NUMBERS DO YOU WANT TO INPUT\n”); int array_size; scanf(“%d”, &array_size); int* … Read more
[ad_1] There’s nothing wrong with having a while loop inside a for loop. To demonstrate: i = 0 kebab = [“chicken”,”garlic”,”cheese”,”tomato”,”lettuce”,”chilli”] print “Kebabs are so good, this is what mine has:” excitement_over_kebab = 1 for ingredients in kebab: while excitement_over_kebab == 1: print kebab[i] i+=1 if i == 6: print “Enough talk, my lunch break … Read more
[ad_1] No, you cannot. Functions cannot be generally declared inside another function. You can only define them. The language was designed like that. Also see these: Function Declaration and Function Prototypes C – Functions Declaring a function – function prototypes I think you need a good C book or tutorial. You can choose a good … Read more
[ad_1] Here is an explanation of everything happening in the for loop // keeps the for loop going while x is less than numbers.length which is the length of nmbers // sets x to 0 initialy | increases x by +1 each time it restarts to begin the loop // V V V for (var … Read more
[ad_1] Mlist = [‘alex’,’peter’,’alan’,’david’] Flist = [‘mary’,’kitty’,’susan’,’amy’] idx=Mlist.index(‘peter’) Mlist.remove(Mlist[idx]) Flist.remove(Flist[idx]) print (Mlist) print (Flist) [ad_2] solved on Python, I want to do this : remove or map list or for loop two lists in same time
[ad_1] Loop for( statement expression; action ) body loop is just a while loop { statement; while ( expression ) { body label_for_continue: action; } } So you can see that everything declared inside will have its life ending outside of for. You can use break to stop loop prematurely and continue to jump back … Read more
[ad_1] Moving the line stringstream aa; just before the line aa << b; solves the problem for me. This is perhaps caused by use of aa both as an input stream as well as output stream. Not sure of the details. Update Here’s your program with a bit of error checking code thrown in. #include … Read more
[ad_1] Just small change in your code- public static void main(String[] args) { int i = -1; for (int j = 0; j < 11; j += 2) { i++; for (int k = i; k < 5; k++) //small change System.out.print(” “); //small change for (int z = 0; z <= j; z++) { … Read more
[ad_1] I will attempt to answer this based off of pulling teeth in the comments, and I’m still not 100% sure if this is even what you are after, but are you after something like this? Changes Input parameter is an array so you can actually iterate over it If statements are properly aligned and … Read more
[ad_1] Instead of logging the result of each character, concatenate them to a result variable, and then output that, once: var puzzle = [0x3c, 0x62, 0x75, 0x74, 0x74, 0x6f, 0x6e, 0x20, 0x6f, 0x6e, 0x63, 0x6c, 0x69, 0x63, 0x6b, 0x3d, 0x27, 0x6a, 0x61, 0x76, 0x61, 0x73, 0x63, 0x72, 0x69, 0x70, 0x74, 0x3a, 0x69, 0x66, 0x20, 0x28, … Read more
[ad_1] Assuming s.subjects is None or some other False value when there are no subjects, and likewise for books for s in students: for subject in s.subjects or []: for book in subject.books or []: writer.writerow(s.name, s.class, subject.name, book.name) More generally, you can write for s in students: for subject in s.subjects if <condition> else … Read more
[ad_1] You cannot access variables like this. You have to define a List or an array int A = 0; int[] myIntArray = {1,2,3,4,5}; for (int i = 0; i < myIntArray.length; i++){ //Now you can access your array with the index A = myIntArray[i]; //This statement still does not make much sense } You … Read more
[ad_1] Well, the problem is that the variable i, within each of your anonymous functions, is bound to the same variable outside of the function. ES6 solution: let ECMAScript 6 (ES6) introduces new let and const keywords that are scoped differently than var-based variables. For example, in a loop with a let-based index, each iteration … Read more