[Solved] Python 3.4 i want creat list 0,24,48,…….6168 [closed]
Yes, you will have to overload the range function for i in range(0,n,24): print(i) Output: 0 24 48 72… 0 solved Python 3.4 i want creat list 0,24,48,…….6168 [closed]
Yes, you will have to overload the range function for i in range(0,n,24): print(i) Output: 0 24 48 72… 0 solved Python 3.4 i want creat list 0,24,48,…….6168 [closed]
The comparator seems correct. The problem seems to be in your filter clause, where you compare the event id to the device id lastDeviceEvent = deviceEvents .stream() .filter (o -> o.getDeviceId().equals(deviceId)) // Original code used getId() .sorted(comparing((DeviceEvent de) -> de.getId()).reversed()) .findFirst() .get(); solved Java 8 comparator not working
You can get all of the indices whose value is x using a list comprehension: indices = [i for i, elem in enumerate(word) if elem == x] So you would have: >>> word = [“p”, “y”, “t”, “h”, “o”, “n”] status = [“_”, “_”, “_”, “_”, “_”, “_”] >>> >>> word [‘p’, ‘y’, ‘t’, ‘h’, … Read more
Let’s see how one would approach this problem without programming and you would able to solve it by applying similar process in pseudocode: (1) Examine each character in aaaa (2) If the character exists in dddd, keep it as it is (3) Otherwise, output – instead We can solve (1) by iterating over aaaa by … Read more
You may iterate on the element of your list, and for each test the expression value-10 < x and x < value+10 that can be written in once in python value-10 < x < value+10 def search_numbers(values, x): for value in values: if value – 10 < x < value + 10: print(f”Ok: {value}-10 < … Read more
You’re returning List<Integer>, but you’re creating an int[]. They’re completely different things! try this instead: private static List<Integer> randomIntegerArray(int n) { List<Integer> list = new ArrayList<>(); for(int i = 0; i < n; i++) { list.add((int) Math.random()); // always returns 0 } return list; } Or if you definitely want to use an array, change … Read more
Use enumerate for count,item in enumerate(input_list,1): # your code print(count) 2 Or you can increment a counter while iterating : count = 0 for i in input_list: count += 1 # your code print(count) 2 solved Counting the number of lists that are printed [closed]
The for loops are nested, from left to right. You can write it out as regular loops like this: words = [] for line in open(‘words.txt’, ‘r’): for word in line.split(): words.append(word) So the expression before the for loops is the final value added to the produced list, and all the for loops (and any … Read more
Try using .extend instead of .append: b_list.extend(c) solved list in def function [closed]
This is a really bad question. However, The last line in your code will fail with This expression was expected to have type int list list but here has type int .. because :: concatenates an element to a list. It can only do it from the front because the list is a singly linked … Read more
You can use reduce (functools.reduce in Python3) if the integer is non-zero >>> x = [False, False, False, 10, False, False] >>> reduce(lambda i,j:i or j, x) 10 You can use a generator expression also here >>> x = [False, False, False, 10, False, False] >>> (i for i in x if i!=False).next() 10 Also … Read more
A very minimal example: stops = {‘remove’, ‘these’, ‘words’} strings = [‘please do not remove these words’, ‘removal is not cool’, ‘please please these are the bees\’ knees’, ‘there are no stopwords here’] strings_cleaned = [‘ ‘.join(word for word in s.split() if word not in stops) for s in strings] Or you could do: strings_cleaned … Read more
public HashMap<String, List<String>> getSortedHashMapForEmployees(string searchKeyword,List<yourDtoFromDB> orginalListFromDB) { HashMap<String, List<String>>hashmap=new HashMap<String, List<String>>(); for (List<yourDtoFromDB> orginalList : orginalListFromDB) { if(orginalList.getName().contains(searchKeyword)) { List<String>accountNo=new ArrayList<String>(); if(hashmap.containsKey(orginalList.getName())) { accountNo=hashmap.get(orginalList.getName()); } accountNo.add(orginalList.getAccountNo()); hashmap.put(orginalList.getName(), accountNo); } } return hashmap; } 3 solved How to search a list and return the specific strings and data associated with it using Java
Try executing this in the directory containing all your movies’ folders : $language = Read-Host “Language to search for” foreach ($folder in (dir -Directory)) { if (-not (Get-ChildItem -Path “$($folder.Name)/*.$language.srt”)) { “Missing $language subtitle for $($folder.Name)” } } 0 solved Search for folders that doesn’t contain file with a wanted name
Ah I see your problem. this is really what i want to do. i want to add tt1 in another list but the thing is this just happen [0, [102, 0.5, 0.591, 0.529, 10, 42, 26, 6, 8, 17, 24], 1, 27, 109, 0.41100000000000003, 0.308, 0.818, 16, 48, 26, 13, 9, 9, 22 When you … Read more