If you want to show the users who liked/disliked a post (or a comment), you will have to insert a new row along with the user-id for each like/dislike. And regarding the multiple-likes problem, you will have to check whether or not there is a row with the same user-id and comment-ids as the ones … Read more
Thank god not much people know about weinre. You can use @media queries to detect the screen size and remove the contents accordingly. @media (max-device-width: 1024) { body { display: none; } } The max-device-width works only on devices and not on desktops. This is a way of doing using CSS. In JavaScript, well, I … Read more
use array find https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find var contacts = [ { firstname: ‘karthi’ , lastname: ‘kosuri’ , mobile: ‘9999666888889’ , likes: [ ‘pizza’, ‘icecream’, ‘curdrice’ ] } , { firstname: ‘sathvik’ , lastname: ‘kosuri’ , mobile: ‘9849488486’ , likes: [ ‘biryani’, ‘vada’, ‘idly’ ] } , { firstname: ‘neelu’ , lastname: ‘kosuri’ , mobile: ‘892736636’ , likes: … Read more
what does the [] mean? [] is a special javascript property access notation . imagine if i have an ojbect like: var o = { “abc.xyz” : 5 }; I can’t say o.abc.xyz , that’s where [] is handy o[‘abc.xyz’]. What’s special with the $? $ is often used as a naming convention with jquery … Read more
Try this, <?php $domain = “www.google.com”; $ip = gethostbyname($domain); echo “Domain: “.$domain; echo “<br>”; echo “IP: “.$ip; ?> solved Fetching the server IP from URL [closed]
Something like this: var url_string = window.location.href var url = new URL(url_string); var id = url.searchParams.get(“id”); window.location.replace(“www.redirectaddress.com/p?id=”+id); //redirect 2 solved How to detect and replace values/parameters in URL on redirection [closed]
If the MasterFolder part of that path is visible to the browser, you just want .. to go up one level: window.location.href = “https://stackoverflow.com/questions/55340635/TextFile2.aspx”; solved How to access aspx file in window.location.href()
Javascript – What is the best way to remove alternate repeating character in a given string with time complexity O(n) and Space Complexity was O(1)? solved Javascript – What is the best way to remove alternate repeating character in a given string with time complexity O(n) and Space Complexity was O(1)?
Did you defined leg, lat and lgn ? Are you using this script in environment with EcmaScript6 (ES2015) or newer version of JavaScript ? If not, this script doesn’t work. EcmaScript6 and newer : var leg = “leg”, lat = “lat”, lgn = “lgn” var waypoints_legs = [{leg,latlgn:{lat,lgn}}] EcmaScript5 and older : ‘use strict’; var … Read more
The element exist there. Probably UI of button is not appearing because of using delays or not rendering in given time but the element exist there. Go to inspect and copy the unique identifier of “Start button” from normal browser(which is not running through automated script) then use await page.click(“button_Identifier”); and you will see start … Read more
No, this is not possible and that’s a damn good thing. We don’t need random websites to act as keyloggers. Any browser plugin allowing a website to do that would actually be malware or at least open a gaping security hole and thus end up on the plugin blacklists of browser vendors really soon. solved … Read more
Here’s a very simple implementation that should work for simple objects like this: var walkProps = function(obj) { var s = “”; for(var x in obj) { if(typeof obj[x] === “string”) s += obj[x]; else s += walkProps(obj[x]); } return s; } Demonstration Note, though, that that depends on the order in which for-in visits … Read more
// if duplicate _id’s are allowed for the desc key const result = […new Set(articles.map(v => v.key))].map((val => ({key: val, desc: articles.filter(v => v.key === val).map(x => x.desc._id)}))); console.log(result); // if only unique _id’s are allowed const result1 = […new Set(articles.map(v => v.key))].map((val => ({key: val, desc: […new Set(articles.filter(v => v.key === val).map(x => x.desc._id))]}))); … Read more
I recommend attempting to google the answer to your question for at least 30 minutes prior to posting on a website such as this, as such queries will usually return useful information. Either way, to create a line-break, you can use \n Integrating this into usable code, you can do, for example: message.channel.send(‘Line one \n … Read more
With the updated structure with an object, you could use the given keys directly, without iterating. All you need is the right property accessor. object.property // dot notation object[‘property’] // bracket notation var scheduleFee = { poor: { level1: 25, level2: 25, level3: 25 }, good: { level1: 15, level2: 20, level3: 25 }, vgood: … Read more