[Solved] syntax error on token “(” , ; expected [closed]
Try cleaning the build. Sometimes that’s all it takes to clean up inexplicable syntax errors. 1 solved syntax error on token “(” , ; expected [closed]
Try cleaning the build. Sometimes that’s all it takes to clean up inexplicable syntax errors. 1 solved syntax error on token “(” , ; expected [closed]
With Java 8 you can use a lambda. With Processing, you can use an anonymous class that implements a functional interface. Something like this: interface DoFunction{ void do(); } void hello(DoFunction function){ function.do(); } void setup(){ hello(new DoFunction(){ void do(){ println(“here”); } }); } 3 solved Java/Processing is that possible ? void hello(void funktion) [closed]
You can convert it to String and then validate it with matches(). 2 solved Validating sql date type in java [closed]
Just follow the documentation and use the formatting elements that correspond to the string you have: String strDate = “12/19/2015 8:00:00 AM”; DateFormat df = new SimpleDateFormat(“MM/dd/yyyy hh:mm:ss a”); Date date = df.parse(strDate); solved How to parse this date in java : “12/19/2015 8:00:00 AM” [duplicate]
The first line that doesn’t make sense to me and shouldn’t complie is this. Names = Names [Y] = myScanner.next(); You are setting the String[] Names to a single String value. 7 solved War – Card Game – With Betting – Java
Individual parameters aren’t iterable; you’d need a collection for that. Try changing it to an array instead: public void increment(int increment1, int increment2, int increment3) { int[] array = {increment1, increment2, increment3}; for(int i = 1; i < array.length; i++){ array[i] = 1; } } or public void increment(int[] increment) { for(int i = 1; … Read more
You can try like this, and your root is Json array not jsonobject try { JSONArray jsonArray = new JSONArray(d); if(jsonArray != null) { for (int i = 0; i < jsonArray.length(); i++) { JSONObject jsonObject = jsonArray.optJSONObject(i); if(jsonObject == null) { continue; } String name = jsonObject.optString(“name”); String isMe = jsonObject.optString(“isMe”); String time = … Read more
You can define a natural ordering for your class IceCream by implementing the Comparator interface. public class IceCream implements Comparator{ // … final String name; final Date date; public Icecream(String name, Date date){ this.name = name; this.date = date; } public int compare(Object o1, Object o2) { return ((IceCream)o1).date.compareTo(((IceCream)o2).date); } } 3 solved sorting (constructor) … Read more
int randomNumber = ( int )( Math.random() * 9999 ); if( randomNumber <= 1000 ) { randomNumber = randomNumber + 1000; Math.random() is a method that generates a random number through a formula. It returns a double however, so casting is required if you want an integer, float, or etc. The if block makes sure … Read more
I think what you want to do here is this: int getLength(int[] arr) { int length = 0; for(int i = 0; i < arr.length; i++) length++; return length; } I am assuming that this is for some sort of homework, and this is just for teaching for loops because this method is complete overkill … Read more
true && !true => false false && !false => false the only other option is Boolean x = null; x && !x => NullPointerException. 2 solved Java -Boolean expression of variable and it’s inverse
@Fay Zan Basically you don’t want user to input more than 9 digits for your field, This can be achieved using two ways programmatically or using layout views properties, In you xml simple give this attribute to your EditText android:maxLength=”9″ OR programmatically by checking the length of your field. for example suppose the id of … Read more
I think this is a quick working not optimized solution. You basically suppose that you can have n parts. If it works you return, if not you suppose that you can have n-1 part and so one. int result = -1; int len = s.length(); for(int i = len; i > 0; i–){ int n … Read more
Use String.trim() to remove surrounding whitespace and then use String.equals() (not ==, See 15.21 Equality Operators in the Java Language Specification for full details.). Remember that String instances are immutable so String.trim() returns a new String and it is that which must be used in the equals() check. Note that trim() removes leading whitespace also. … Read more
By the time program control gets to else if(!visible){, visible can only be false. Your compiler is hinting that you should clarify your code to else { instead. solved Why isn’t the compiler noticing that a boolean has been declared true?