Change JSONArray list = new JSONArray(Jo_result.getString(“result”)); To JSONObject list = new JSONObject(Jo_result.getString(“result”)); Your string is contained between {} which makes it an object. Keep in mind this {} = Json Object [] = Json Array UPDATE When you do this JSONObject resultsObject = list.getJSONObject(i); it’s expecting another object within the main object, for example : … Read more
I solved it by using YaHP Converter, if somebody else wonders, just take a look at their site. http://www.allcolor.org/YaHPConverter/ solved Convert .jsp or html file to pdf [closed]
The apache http client makes this a piece of cake. Check the following tutorial for more details : http://www.vogella.com/tutorials/ApacheHttpClient/article.html http://www.mkyong.com/java/how-to-send-http-request-getpost-in-java/ solved convert curl to httpclient post [closed]
You can replace the space character with “like”: text.replace(” “, ” like “); solved Write method that puts the word “like” in between each of the words in the original sentence
In your for loop: Remove the semicolon (;) just after the for(int rolls= 1; rolls==trials; rolls++) line. Change: for(int rolls= 1; rolls==trials; rolls++) to: for(int rolls= 1; rolls<=trials; rolls++) As far as changing switch to if–else–if, not sure why you would want to do this, but simply write it as: if(face == 1){ one++; } … Read more
How to handle Alerts in chrome 64 using selenium Java?Getting chrome pop up as ” Do you want to leave this site?” [duplicate] solved How to handle Alerts in chrome 64 using selenium Java?Getting chrome pop up as ” Do you want to leave this site?” [duplicate]
thanks to all…..the thing which i dont know was – during a function call if i want to pass an array(arr[]) as argument then i just need to pass its name(arr) as argument not the square brackets([]) along with it. Here is my new optimized error free code which has been submitted successfully. import java.util.*; … Read more
I recommend you use do-while loop (it doesn’t mean you can’t solve it using other types of loop) because it will make the code easy to understand. A do-while loop guarantees that its body will be executed at least once. You also need a variable, e.g. int attempts to track the number of attempts. Do … Read more
Problem is in your odbc connection goto ControlPanel->AdministrativeTools->DataSource(ODBC)->System DSN->ADD->SqlServer-> then in the name field give the Source Name. you have to use this name instead of testdb in your DriverManager.getConnection method. Because getConnectionMethod take the source name not the database name. so your code is not working. However after filling the source name fill the … Read more
You may try this: public void ClickButton () throws InterruptedException { WebElement button = driver.findElement(By.id(“button”)); String Source = driver.getPageSource(); if (Source.contains(button)) { button.click(); Thread.sleep(3000); } else { driver.quit; } } Hope this can be helpful. Let me know if you are still facing problem. solved Using IF commands to Check if a button exists in … Read more
you have to write following in onCreate after setContentView() Button btnplus = (Button)findViewById(R.id.btnplus); RatingBar ratingbar = (RatingBar)findViewById(R.id.ratingBar); like below. public class MainActivity extends AppCompatActivity { Button btnplus; RatingBar ratingbar; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); btnplus = (Button)findViewById(R.id.btnplus); ratingbar = (RatingBar)findViewById(R.id.ratingBar); } public void plusonclick() { if (ratingbar.getRating() == 1) { setContentView(R.layout.activity_plusrechnenlvl1); } … Read more
Try below java code public static int[] reverse(int[] a, int number) { // negative case if (number < 0) { return a; } // higher count than array length int size = number < a.length ? number : a.length; int[] b = new int[size]; System.arraycopy(a, 0, b, 0, size); for (int i = b.length – … Read more
This will fill the array with a range of 1 – N: public class NurTests { public static void main(String[] args) { int [] arr = new int[100]; int value = 1; for(int i = 0; i < arr.length; i++){ arr[i] = value; value ++; } } } A simpler way to do it, you … Read more
you need check focus on editText and set AnimatioValue edt.setOnFocusChangeListener(new View.OnFocusChangeListener() { @Override public void onFocusChange(View arg0, boolean hasfocus) { if (hasfocus) { Log.e(“TAG”, “edt focused”); //ValueAnimator total ValueAnimator valueAnimator = ValueAnimator.ofFloat(1f, 1.5f); valueAnimator.setDuration(325); valueAnimator.addUpdateListener(new ValueAnimator.AnimatorUpdateListener() { public void onAnimationUpdate(ValueAnimator animation) { float value = (Float) animation.getAnimatedValue(); edt.setScaleX(value); edt.setScaleY(value); edt.requestLayout(); } }); valueAnimator.start(); } else … Read more
Try with below code: JSONObject object = new JSONObject(YOUR RESPONSE STRING); JSONArray jArray = object.getJSONArray(“latlong”); for (int i = 0; i < jArray.length(); i++) { String lat = jArray.getJSONObject(i).getString(“lat”); String lon = jArray.getJSONObject(i).getString(“lon”); } 14 solved Get latitude and longitude from json data [closed]