Based on your comment A user can input multiple integers the amount is unknown. Ex: 3 4 5 1. There is a space inbetween them. All i want to do is read the integers and put it in a list while using two scanners. You are probably looking for: scanner which will read line from … Read more
Just use this. BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String line; while((line = br.readLine())!=null){ // you can stop taking input when input line is empty if(line.isEmpty()){ break; } System.out.println(line); // printing the input line } br.close(); See live demo 4 solved How to read a string from user with spaces
It looks like you’re making good progress. One problem that jumps out is that you’re thinking of the second expression in a for loop as “stop when this is true.” So you’re thinking: for (int i = -10; i == 10; i++) { will keep looping until i == 10 is true. But in fact, … Read more
Answering the question in the title line: If you use java.util.Vector<E>, then it is addElement. Those would be the closest-match class and method in Java to the C++ template classes that you mentioned in your question. Docs are here: https://docs.oracle.com/javase/8/docs/api/java/util/Vector.html#addElement-E- 2 solved what is the method equivalent to push_back (C++) in java?
If you want it static you will have to do it like this: public static Vecteur somme(Vecteur v1, Vecteur v2) { Vecteur u = new Vecteur(v1.x + v2.x, v1.y + v2.y, v1.z + v2.z); return u; } The only way to do it with just one parameter and being able to use your own values … Read more
Your solution is has O(n^2) time complexity – those nested loops will be very slow for large lists. However, with the aid of a HashMap, an O(n) solution is possible. Map<String, NameAndValue> map = new HashMap<>(); for (NameAndValue x : arrayB) map.put(x.getName(), x); for (int i = 0; i < arrayA.size(); i++) arrayB.set(i, map.get(arrayA.get(i).getName())); This … Read more
I don’t really see the problem. In addition to creating a new certificate, you actually have to use it when you sign. If you use the old one it doesn’t matter. And it isn’t the keystore (a keystore can contain multiple certificates) that is the problem. you have to make sure you use the right … Read more
Switch is a reserved word in Java. Used for the switch … case construct. You have named your method switch, which is not allowed. The first group of errors you are getting are because when you use j = switch(j), it sees the word switch as the start of a switch construct and then tells … Read more
The Integer.getInteger(String) method states the following: The first argument is treated as the name of a system property. System properties are accessible through the System.getProperty(java.lang.String) method. The string value of this property is then interpreted as an integer value using the grammar supported by decode and an Integer object representing this value is returned. If … Read more
It should be: while (number < maxNumber){ number++; System.out.print(number); } Note the misplaced semicolon. 0 solved While loop won’t work in java [closed]
How about something like this: String getRandomString(List<String> list) { return list.get(new Random().nextInt(list.size())); } This isn’t the most efficient way, but should do the job. 5 solved Return method return several times [closed]
As the comments have suggested you need to change the return type of the function to return int and you need to return your damageDelt variable. One way to do this is declare it outside of your if statements and then return it at the end of the function. If you didn’t want to do … Read more
Change your code to this: String[][] content_split = new String[string_array.length][]; // create 2d array for (int i=0; i<string_array.length; i++){ content_split[i] = string_array[i].split(” : “); // store into array and split by different criteria } Which leaves you with a 2D array of your split content. solved Looping a string split from an array [closed]
Split on “,”. String st = “Tokyo, New York, Amsterdam” String[] arr = st.split(“,”); If st has ‘{‘ and ‘}’. You might want to do something along the lines of… st = st.replace(“{“,””).replace(“}”,””); to get rid of the ‘{‘ and ‘}’. 1 solved How to convert String into String Array in Java? [duplicate]
The only difference between println and print method is that println throws the cursor to the next line after printing the desired result whereas print method keeps the cursor on the same line. More information 4 solved System.out.print vs. System.out.println (Last sentence)