This is because you have created AVD for Wearable devices. I assume that you are creating an AVD for smart phones. Please see this Make sure you have downloaded the API level 17,18,19 packages. If not Navigate in Eclipse to Window – >Android SDK Manager and download the API packages as shown in the below … Read more
Simply pass the object of the created ArrayList to the function as paramter. Here’s a short example for printing the ArrayList: Assuming you put the code inside a class, leaving a snippet here. I’ll demonstrate it with Integer examples. static void printArrayList(ArrayList<Integer> a){ for(Integer i:a) System.out.print(i+” “); System.out.println(“”); } //in the main function: public static … Read more
Reads & prints the content public static void main(String[] args) { List<String> li=new TestClass().textFiles(“your Directory”); for(String s:li){ try(BufferedReader br = new BufferedReader(new FileReader(s))) { StringBuilder sb = new StringBuilder(); String line = br.readLine(); while (line != null) { sb.append(line); sb.append(System.lineSeparator()); line = br.readLine(); } String everything = sb.toString(); System.out.println(everything); } catch (IOException e) { e.printStackTrace(); … Read more
You minising for me. ok. But it’s better to give some available solutions to the problem. But it is easier to place minuses. This is solution for the ListPreference, workable for lower then HoneyComb android too : public class IconPreference extends ListPreference { private Drawable mIcon; public IconPreference(Context context, AttributeSet attrs) { this(context, attrs, 0); … Read more
You can use below code which uses HashSet() in Java. public static boolean hasPairWithSum2(int arr[], int sum){ HashSet<Integer>mySet=new HashSet<Integer>(); int len = arr.length; for (int i = 0; i < len; i++){ if (mySet.contains(arr[i])) return true; mySet.add(sum – arr[i]); } return false; } 1 solved What can I use instead of Set() in Java?
If I interpreted your question correctly, you’re not really confused about the recursion part, you’re more confused about how the value num gets assigned to num – 1 part. The answer to this is that num is never being reassigned in the first place, at least not in its own lexical scope. What that basically … Read more
It’s because the contract for the equals method, as specified in the Javadoc for the Object.equals method , explicitly states: For any non-null reference value x, x.equals(null) should return false. If the method threw a NullPointerException, it would be non-compliant with the contract. solved Why doesn’t equals throw NullPointerException when one of the variables is … Read more
The reason we have default methods in interfaces is to allow the developers to add new methods to the interfaces without affecting the classes that implements these interfaces. Here is link for complete article. 0 solved Why can I define only default and static methods inside a java interface? [duplicate]
First of all, use a memory profiler such as YourKit to figure out what it is exactly that’s consuming the memory (for example, it could be due to the accidental retention of some unneeded references). Once you understand how your program is actually using the memory, you can formulate a plan of attack. solved out … Read more
You have two nested loops that each execute anyLines.length times. If there are four lines in the file, the inner loop will execute 16 times. 2 solved Why is this code looping 16 times? [duplicate]
You never instantiated builder. You need to say builder = …; Also, you can’t have private fields inside a method. Delete the private keyword. 2 solved Java file uri with xml file null pointer exception [closed]
Your activities are indeed classes. Look at the declarations! public class MainActivity extends Activity { ^^^^^ // see? it’s a class! And the class is in whatever package it says on the top of the file. e.g. package com.example.myapp; every new activity has it’s own XML I guess this is where you are most confused. … Read more
You just need backslash to escape: System.out.println(“\”” + s + “\” ” + GM); Output: “Juan” GOOD MORNING 1 solved how to separate string with special character in Java
You need to get the result by using substring method as below String total_points = potential_points.getText(); int startIndex=total_points.indexOf(“:”)+2; int endIndex=total_points.length(); String result=total_points.substring(startIndex,endIndex); int no=Integer.parseInt(result); Simplified the above code as below String result=total_points.substring(total_points.indexOf(“:”)+2,total_points.length()); int no=Integer.parseInt(result); 15 solved Extract a number from a string getting number format exception
Change your build dependencies to use: com.firebaseui:firebase-ui:3.2.1 That is the version compatible with Firebase SDK 11.8.0. solved Firebase Error(Android Studio) [closed]