Your best way of doing this, is probably going to be a list comprehension. user_input = raw_input(“Please enter five numbers separated by a single space only: “) input_numbers = [int(i) for i in user_input.split(‘ ‘) if i.isdigit()] This will split the user’s input at the spaces, and create an integer list. 1 solved User input … Read more
You cannot use a regular int declaration for an array unless you include brackets in the variable name answer[]. Also, array values are defined with curly braces: int count = 0; int[] answer = {2,4,3,2,1}; or int count = 0, answer[] = {2,4,3,2,1}; 3 solved Array answer[i] to if Java
Using the regular expressions as suggested by AChampion, you can do the following. string = “44-23+44*4522″ import re result = re.findall(r’\d+’,string) The r” signifies raw text, the ‘\d’ find a decimal character and the + signifies 1 or more occurrences. If you expect floating points in your string that you don’t want to be separated, … Read more
What does this code do? How would have you named such a function? I would have named it so /// <summary> /// Convert an Int32 value into its binary string representation. /// </summary> /// <param name=”value”>The Int32 to convert.</param> /// <returns>The binary string representation for an Int32 value.</returns> public String ConvertInt32ToBinaryString(Int32 value) { String pout … Read more
Here is a very simple example to process your file and split the string line and obtain the date object. public class FileReaderExample { public static void main(String[] args) { File file = new File(“d:\\text.txt”); try { BufferedReader br = new BufferedReader(new FileReader(file)); String line; int lineNo = 1; while ((line = br.readLine()) != null) … Read more
If I understand you correctly, you want to add random number to every candidate key number. If that is the case try this. var candidatekey = new List<int> { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; var randomnumber=42; //we are using LINQ on list candidatekey=candidatekey.Select(c => c+randomnumber).ToList(); 1 solved Concatenating int and … Read more
I feel bad writing this answer, but hopefully this will prevent all other answers and close the ticket. private static int ToPercentage(double d) { return (int)(d*100); } EDIT: Thanks Devid for the suggestion 🙂 TIL how to make an answer a community wiki post! 2 solved Converting decimal percentage to int
This should work: for (int i=1; i<=4; i++) { for (float j=i; j<=std::max(1.6, i); j+=0.5) { cout << j << endl; } } The above code will print the desired sequence. 6 solved int and float increment condition in for loop [closed]
So in a for loop, when declaring the temp variable “i” you need to declare it as int i = 1; instead of “i = 1” I assume you already have a value for the variable d but in this case, I just used d = 123. int d = 123; for (int i = … Read more
thanks to everyone who gave a answer 😀 much appreciated i got it working like this in the end int employmentInMonthsAmount = this.MaxEmploymentHistoryInMonths; var intcounter = 0; int years = 0; for (var i = 0; i < employmentInMonthsAmount; i++) { if (intcounter >= 12) { years++; intcounter = 0; } intcounter++; } var monthsleft … Read more
The printf function has the following declaration: int printf(const char *format, …); The first argument must be a pointer to a char array, but any additional arguments can be of any type, so it’s not a compiler error if a format specifier mismatches the parameter (although it is undefined behavior). This still works however because … Read more
TL;DR It is completely possible to have a language without pointers. Actually, it is possible to write a C program where you store addresses in regular integer variables and then cast them to pointers. Calling pointers, and also the general concept of types, syntactic sugar is to stretch it a bit, but it’s not completely … Read more
The first method you are calling is Read which returns one character. But it blocks until you hit the Enter key. From MSDN: The Read method blocks its return while you type input characters; it terminates when you press the Enter key. Then you call ReadLine which returns a line. When you hit the Enter … Read more
This is not because of the complier. It is happening because you are doing i /= 10; //slice end So when you do 13.4 after the first run it wont give you 1.34 it will give you something like 1.339999999999999999 which is 1.34. Check Retain precision with double in Java for more details. If you … Read more
You can use strconv from the strconv package package main import ( “fmt” “strconv” ) func main() { a := 4 b := 3 c := “1” fmt.Println(c + strconv.Itoa(a) + strconv.Itoa(b)) } Or you can use Sprintf from the fmt package: package main import ( “fmt” ) func main() { a := 4 b … Read more