[ad_1] The following declaration within a definition of your class is not enough: private: static map_type * map; In one .cpp file, you must also add: map_type* BaseFactory::map = NULL; This article might help you too: Static data members (C++ only) + this question, which has almost 100k views by now: Initializing private static members … Read more
[ad_1] You practically already answered your question: Because declaration does not assign a value. Therefore your second sample never makes sense. The first sample consists of two separate statements each of which could make sense in a certain context. Therefore it compiles. 1 [ad_2] solved Why can’t variables be declared and modified at once? (C++)
[ad_1] Even easier than that. Behold the power of uniform initialization: foo({1,2}); [ad_2] solved Is it possible to create temp structs/classes with initializer lists? [closed]
[ad_1] You never call your method “forloop()”, that’s the reason why there’s nothing printed. NewbieJavaDeveloper’s answer is a good one. But if you want to pactice “method and return”, here is another answer: import java.util.Scanner;//import scanner so user can input class arrays { public static void main(String[] param) { String[] animals = arrays(); forloop(animals); System.exit(0); … Read more
[ad_1] What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ? [ad_2] solved What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ?
[ad_1] Excellent idea! Here’s a program that prints “hellohello” five times: int i; void print_twice(const std::string& s) { for (i = 0; i < 2; i++) { std::cout << s; } std::cout << std::endl; } int main() { for (i = 0; i < 5; i++) { print_twice(“hello”); } } Or… does it? (Ominous organ … Read more
[ad_1] You’re hitting undefined behavior for the below line result = result*num; as you’ve not initialized result. The initial value for an uninitialized automatic local variable is indeterminate. Using that invokes UB. Always initialize your local variables, like int count = 0 , result = 0 ; //0 is for illustration, use any value, but … Read more
[ad_1] A structValue{}; is aggregate initialization, so 0 are guaranteed. As A has no user provided constructor because explicitly defaulted constructors do not count as such, the same applies for value initialization as in A* psstructValue = new A();. For the default initialization cases: Reading uninitialized variables is UB, and Undefined behavior is undefined. The … Read more
[ad_1] In Visual Studio C++, what are the memory allocation representations?: 0xCCCCCCCC : Used by Microsoft’s C++ debugging runtime library to mark uninitialised stack memory At the moment you do obj->, your obj is not initialized. The two lines of code in the question are not your real code, or there is something important taking … Read more
[ad_1] Well the message is clear and it is easy to spot in your program: double gallons,miles; while (miles>=0||gallons>=0) { miles is declared in a function and so is an automatic variable. Automatic variables are not initialized (so they have garbage values). Now in the first executable statement you compare miles. But miles is still … Read more
[ad_1] To pass literal string to a function, it must have a parameter of type char const *, not char *. So your constructor should have this prototype: Etudiant(char const * c, unsigned int, Date &); Saying the above, you also do not allocate enough memory to copy a string in your constructor. This line: … Read more
[ad_1] yes you can initialize an object without any parameters, let me explain simply, an object is just a copy from a class, it has a copy of all the public methods and fields inside this class. We use objects to access members of a class so let’s assume you have two classes X and … Read more
[ad_1] UPDATE FOR THE NEW CLEARER QUESTION: It sees now that I should have added more text to my question. I wanted to know what would be the sequence of execution in case both these statements(1 and 2) are in one single class for the same variable ? You are interessted something like this: private … Read more
[ad_1] { x = a; y = b; } is the compound statement of the constructor point( int a = 0, int b = 0 ); Maybe it will be more clear if to rewrite the constructor like point( int a = 0, int b = 0 ) { x = a; y = b; … Read more
[ad_1] String.valueOf().length() returns 11 because that is the number of digits/characters in the output (i.e. [@936016386 – an address – has 11 characters) [ad_2] solved How do I properly test the char[ ] fields in my custom object for nulls, blanks, or empty? and Why do char[ ] indicate a length of 11?