Presumably rhs is empty, and so rhs[0] does not exist. Hence an index out of bounds exception is thrown. Try if(!String.IsNullOrEmpty(rhs) && rhs[0] == ‘+’) … 3 solved Index out of bounds in an if statement [closed]
You must realize that 12 does not divide 52, and that there are not 4 weeks to every month. So to give an example that you can fine tune to get exactly what you want, I’ve defined a week to belong to the same month that its thursdays belong to. This dovetails nicely with the … Read more
It’s line 5: if (!userGet($username,$conn){ Should have 2 closing brackets if (!userGet($username,$conn)){ solved bracket is lost in PHP code [closed]
i hope now you will able to understand the concept of Logical AND (&&) :- Condition 1 Condition2 Output true true true true false false false true false false false false one the TRUE + TRUE Output will be TRUE otherwise output will be FALSE. solved Result from printing statement and if statement differ
This might be slightly off as mysql dialect always throws me. Since B falls after A in an alphabetical sort, if you group on the ID and then select the maximum, it will give you all the B rows where they exist, otherwise you will get the A row. SELECT ID, MAX(alphabet) AS preference FROM … Read more
On some systems keyboard can repeate sending key event when it is pressed so with pynput you would need only this (for key ‘a’) from pynput.keyboard import Listener, KeyCode def get_pressed(event): #print(‘pressed:’, event) if event == KeyCode.from_char(‘a’): print(“hold pressed: a”) with Listener(on_press=get_pressed) as listener: listener.join() But sometimes repeating doesn’t work or it need long time … Read more
You can’t do query = input like that. It has to be query = input(“Please select…”). It should match guess = input(“Password: “) above. 1 solved Inputs not triggering if statments in python [closed]
Sui_Q1<- list() is written more than once. it cause the list() to override. The solution is only to put Sui_Q1<- list() and Sui_Q2<-list() before looping. solved R : assigning value in looping and else if
You got 3 ways to write a function which are effectively doing the same thing. They are all assigning _p with the value of p if the value of p is not negative. (void) in your function says that it is not going to return anything. Therefore the return; is not doing anything but exiting … Read more
For starters there is no elseif statement in C++.There are if and if-else statements in C++. Also you have to remove mistaken semicolons at the end of if or else with if statements. And the conditions are also written incorrectly. A valid else statement can look for example like else if ( dateOfBirth == 2009 … Read more
The Python if ternary operator syntax requires an else, like so: x = 2 if y < 5 else 4 solved Shorthand ‘if’ is throwing a syntax error
As the comments have suggested you need to change the return type of the function to return int and you need to return your damageDelt variable. One way to do this is declare it outside of your if statements and then return it at the end of the function. If you didn’t want to do … Read more
A possible solution is to use do…while. This code will keep display alert(‘invalid number of grades, please insert again’) and window.prompt until it meets you condition. Then it will window.prompt for user to enter the number. const grades = []; let gradeAmount = Number(prompt(‘insert a number between 1 and 5’)); do{ if(gradeAmount < 1 || … Read more
As far as cpu time – NO DIFFERENCE. The compiler will probably optimise them to exactly the same byte-code anyway. As far as technical debt is concerned – as soon as a real developer looks at this code and replaces it with: private static final String[] numbers = {“ZERO”, “ONE”, “TWO”}; private String getString(int n) … Read more
You have a small syntax error in that line of code. Instead of if (checkWin()); it should be if (checkWin()) Remove the ; solved Strange if statement always running even if conditions are not met [closed]