Line 1 : Array Declaration.Line 2 : Then you run a loop for a half of the array.Line 3,4,5 : alternating the number like this shown below. Line 6 : Print it in the console window. solved How is it…
your value at key[18] is “L” so if condition is always true and you will get an alert with value 7 1 solved Javascript for loop with if statement not reaching the else if statement [closed]
This is what I was looking for avgDelay <- function(carrier, dest) { TempTotal = 0 TempCount = 0 for(i in 1:dim(delays)[1]) { if(delays$CARRIER[i] == carrier & delays$ARR_DELAY[i] >0 & is.na(delays$ARR_DELAY[i]) == FALSE & delays$DEST[i] == dest) { TempTotal <-TempTotal +…
for ( a = line.getSize() – 1; a >= 0; a–); test(a, line); } You have a semicolon at the end of your for loop. What happens is that the for loop loops but never executes test. So a is…
You just need to see the pattern and replicate it in your code. Here is one way to solve this, which can also be used to produce larger matricies (set the max variable to a different value): public class main{…
Pointing out the mistakes/unnecessary lines in your code: The line split = strings.split().upper() is erroneous and at the same time unnecessary as you are mistakenly using strings (list) instead of string (string literal). Also, you can use len(string) directly instead…
public class Arraymini { public static void main(String [] args){ int [] testArray1= {1,6,3,9,2}; double [] testArray2= {2.3, 8.66, 6.5, -9.2}; printArray(testArray1); printArray(testArray2); } public static void printArray(int []k){ for(int i=0; i<k.length; i++){ System.out.println(k[i]+” “); } } public static void…
You should do a string interpolation or create an Array and then push the values to it. In the end, you would append the entire string, or use the Array.prototype.join to turn it in a string. The for loop is…
Your use of for does not behave as you expect. You’re using this for-comprehension: for (data <- category(i)) { if (data.startsWith(x)) true else false } This expression “desugars” into (i.e. is shorthand for): category(i).foreach(data => { if (data.startsWith(x)) true else…
You are doing the math wrong. The answer would be 1+2+3+4+ … upto n-1 and not 1*2*3 … n solved How many times will “Hello World” be printed?
You can do it that way. It works very nice. $str =array(); for($i=0;$i<10;$i++) { for($j=0;$j<10;$j++){ $str[]=$i; } $j=0; } echo implode($str,’,’); 2 solved Increment number php every next number
I don’t understand why you want to get rid of forEach, but you have the answer and it’s simple as this: for (let i = 0; i < images.length; i++) { const oImage = new Image(); oImage.onload = () =>…
You could just iterate until 5 instead of 6 and print your message out of the loop: for counter in range(5): # Remove the if statement: # if counter == 5: # print(“”) # break myCar.accelerate() time.sleep(1) print(“Maximum speed reached!”)…
When you declare the object inside the loop, a new object will be created on each iteration and the exising one destroyed at the end of each iteration. This is because the object will have a scope inside the {}.…
This line: $i = $integer; …is redundant, as soon as you say for($i = …, $i will be overwritten. In your case, so it should be. Take that line out to start with. Second, I think the problem you’re having…