It will decrement the value by 1 for each iteration This value is called as step which tells the for loop to how to get the next value for the iteration. It can be both negative and positive, but not zero. the positive step means it will increase the iteration value from the first argument … Read more
The most analagous way to do it the way you describe it would be to use two variables left (l) and right (r) that will iterate the string and get their base values using ord(char) – ord(‘a’) + 1: my_string = “World” my_string = my_string.lower() l = 0 r = len(my_string)-1 total = 0 while … Read more
public static void loopingIssue(Integer totalItems, Integer range) { IntStream.range(0, totalItems).filter(i -> i % range == 0) .mapToObj(e -> mapToGroup(e, totalItems, range)) .forEach(System.out::print); } public static String mapToGroup(Integer e, Integer totalItems, Integer maxRange) { if (e + maxRange >= totalItems) { return e + “-” + (totalItems – 1); } else { return e + “-” … Read more
This should work: for (int i=1; i<=4; i++) { for (float j=i; j<=std::max(1.6, i); j+=0.5) { cout << j << endl; } } The above code will print the desired sequence. 6 solved int and float increment condition in for loop [closed]
nums.count(val) counts how many instances of val are in nums. for i in range(nums.count(val)):… is a loop that iterates nums.count(val) times, or, in other words, it iterates as many times as the number of val‘s in nums. i does not actually do anything here, so the more “Pythonic” way of writing that would be to … Read more
So in a for loop, when declaring the temp variable “i” you need to declare it as int i = 1; instead of “i = 1” I assume you already have a value for the variable d but in this case, I just used d = 123. int d = 123; for (int i = … Read more
① You are nesting lists although you just want a flat list (of functions). See the answer of @BartoszKP on that. ② You want to create functions based on local variables. You can do this using lambdas, as @Harsh is proposing, or you can do it using defaulted variables: def F_analytic(k, m, c, f=f): # … Read more
Just Change Inner for loop : here for k=i-1 as you are checking for i>9 and i<9 so 11 will be excluded. I guess you are trying to manage space between two digit and one digit number. But you can just use single for i<=10 and double space for i>10 for (int k = 20; … Read more
“Whenever i choose 1 as my parameter, i enter 3 as my instruction classes however i am unable to input the CPI of class 3 or even the instruction count of class 3. Once i input the CPI and instruction count of class 2 it ends.” This is because you tell it to. Here: for(a … Read more
One particular use is to check even / odd: for($i=0; $i<10; $i++) { if($i%2==0) echo “even” else echo “odd” } This idea could be used to color rows (tr) of a table differently for better presentation. Another use is to close TR dynamically in a complex code (lets say, change tr after every 4 tds). … Read more
I don’t think this loop is a good candidate for a foreach loop. If you were to do so, it would look something like this: var codeLengths = new[] { 4, 3, 2, 1 }; foreach (length in codeLengths) { if(xmlGenioCodes.SelectSingleNode(String.Format(“GenioCodes[Code =\”{0}\”]”, strCodeMX.Substring(0, length))) != null) { strCodeMXLayer = strCodeMX.Substring(0, length); break; } } EDIT … Read more
I am not sure what exactly you are stuck on based on your question so I made a minimal C program with comments I declared an int array who’s first and second dimension are at least 10 because you iterate both i and j from 0 to 9 (inclusive). This is to avoid out of … Read more
You defined your function to be getScore() but you’re calling getScores(), so as would be expected this throws an error because the function you’re calling doesn’t actually exist / hasn’t been defined. Addendum: Since you changed your question, after fixing the previous error. Likewise you’re calling grades, but grades is defined in your other function … Read more
It has to do with how the program source code is interpreted. range(a) will be executed before the body of the loop, producing an iterable object which yields 3, 4, 5. a will be modified later but it will not affect range(a) cause it has already been executed. The following will do what you want, … Read more
Dont do int characters [] [8]; , but string characters [] [8]; . The type you specify at the start of the array declaration is the type of info the array will store. Peace. 6 solved Placing Random String values into an int Array