If you have the paid date as a string: if(strtotime(“2012-10-19 13:13:20 +3 years”) > time()) { // expired } If you have paid date as a timestamp: if(strtotime(“+3 years”, $paidDate) > time()) { // expired } 3 solved PHP DateTime, paid date + a year term [duplicate]
try dic.Values.OrderBy(i=>i.CreatedDateTime) 0 solved How to sort dictionary by DateTime attribute of the value
import datetime d0 = datetime.datetime.strptime(“0001-1-01”, “%Y-%m-%d”) df = datetime.datetime.strptime(“2002-3-14”, “%Y-%m-%d”) print(df-d0) >> 730922 days, 0:00:00 0 solved Turn a datetime into days in python [closed]
I think there is a bit of a confusion here what the string concatenation does to your values. It is nothing less than simply using the default format for a parameterless ToString()! Each of your strings like Debug.Log(“currentTime: ” + currentTime); basically internally implicitly equal Debug.Log(“currentTime: ” + currentTime.ToString()); In that case the ToString() without … Read more
As has been stated A is already a Python tuple, there is no need to convert it into a string first and attempt to parse using a regular expression. If you are trying to write this data to a CSV file, the tuple can be written directly as follows: import datetime import csv A = … Read more
Use the string.prototype.match method: var str = “/Date(1396505647431)/”; str.match(/Date\(\d+\)/)[0] gives “Date(1396505647431)” var time = new Date(+str.match(/\d+/)[0]) gives Thu Apr 03 2014 11:44:07 GMT+0530 (India Standard Time) time.toLocaleTimeString() gives “11:44:07 AM” DEMO solved How to extract a string from a line of characters? [closed]
You can parse your String as DateTime like var text = “24/02/2017 13:57:53”; var dateTime = DateTime.Parse(text); And then you can access the time like var time = dateTime.TimeOfDay; 0 solved How to get time only with date and time in C# [closed]
The bit you seem to be missing is that when the user enters for example “Monday”, you need to convert this string into something that Java can understand as a day of week. This is done through parsing. Fortunately using java.time, the modern Java date and time API, it is not so hard (when you … Read more
Moving juharr’s comment as an answer, as it is correct Simply change: DateTime startDate = endDate.AddMonths(-6); to DateTime startDate = new DateTime(date.Year, date.Month, 1).AddMonths(-5); solved How to get an exact 6 month date range?
Try this: string s = “10.11.2017. 0:00:00”; DateTime expireDate = DateTime.ParseExact(s, “dd.MM.yyyy. H:mm:ss”, CultureInfo.InvariantCulture); 2 solved String was not recognized as a valid DateTime even if I provide valid Date format [closed]
When working with dates and times, it is almost always best to convert the date first into a Python datetime object rather than trying to attempt to alter it using a regular expression. This can then be converted back into the required date format more easily. With regards to leading zeros though, the formatting options … Read more
Something like this? string output = DateTime.Now.ToString(“yyyy-0MM-ddTHH:mm:ss:fffZ”); I’m not sure about the “Z”, if you wanted some time zone info. I zero padded the month like your example. Obviously there would never be a needed third decimal place. 1 solved Getting specific datetime format in C#
You should use K format specifier, since it represents timezone offset string format = “yyyy-MM-ddTHH:mm:ss.FFFK”; or zzz, which means signed timezone offset string format = “yyyy-MM-ddTHH:mm:ss.FFFzzz”; You also might change DateTimeStyles to AdjustToUniversal to get 5/14/2020 1:37:49 PM date, otherwise it’ll be adjusted to local time DateTime d; DateTime.TryParseExact(f, format, CultureInfo.InvariantCulture, DateTimeStyles.AdjustToUniversal, out d); 0 … Read more
Your problem is that you are formatting your dates in %d-%m-%Y format, which will not work in a BETWEEN expression because it uses string comparison; for example the date 10-01-2999 would be between 09-01-2022 and 11-01-2022. You need to format them as %Y-%m-%d for BETWEEN to work correctly. If the dates in your table are … Read more
To benchmark code, you can use microtime() http://php.net/manual/en/function.microtime.php <?php echo ‘modify: ‘; $time = microtime(1); for ($x = 0; $x < 10000; $x++) { $datetime = new DateTime(‘2013-01-29’); $datetime->modify(‘+1 day’); } echo $datetime->format(‘Y-m-d H:i:s’); $end = microtime(1); $time = $end – $time; echo $time . “\n”; echo ‘interval: ‘; $time = microtime(1); for ($x = … Read more