Regardless of whether the type of c is a reference type or a value type, when setting a variable c = something, you are overwriting whatever the variable referred to. So the original object that c referred to is no longer referenced. This does not change the list from updating its reference either though, that’s … Read more
You can do like this, Collections.sort(matchedWords, new Comparator<String>() { @Override public int compare(String lhs, String rhs) { return lhs.compareToIgnoreCase(rhs); } }); 1 solved Collections.sort() not sort truely [closed]
You can do something like. If you cant guarantee the string formats then you may have to add additional checks for spliced array length and indexing. import java.util.ArrayList; import java.util.List; import java.util.regex.Matcher; import java.util.regex.Pattern; class CustomClass { String name; int num1; int num2; int num3; public CustomClass(String name, int num1, int num2, int num3) { … Read more
You can use List#grouped to create a non-overlapping window: list.grouped(2).map(l => (l(0), l(1))).toMap 7 solved How to convert a list of string to map in Scala?
One example of such method could be: static bool IsSorted<T>(IEnumerable<T> enumerable) where T : IComparable<T> { T prev = default(T); bool prevSet = false; foreach (var item in enumerable) { if (prevSet && (prev == null || prev.CompareTo(item) > 0)) return false; prev = item; prevSet = true; } return true; } Works with most … Read more
Create your Comparator: // Here T is your class name public class Test implements Comparator<T> { @Override public int compare(T o1, T o2) { return (o1.getNumber() – o2.getNumber()); } } And pass it to Collections.sort: Collections.sort(yourList, new Test()); solved How to sort an ArrayList by comparing the element’s property?
There are many tutorials available. Start with these: Product Types in magento Related products, Up-sells, Cross-sells in Magento Product Collections in Magento solved Magento tutorial to work with product collections and databases
Like this: import java.util.*; Set<Integer> a = new HashSet<Integer>(); a.add( 1); a.add( 2); a.add( 3); Or adding from an Array/ or multiple literals; wrap to a list, first. Integer[] array = new Integer[]{ 1, 4, 5}; Set<Integer> b = new HashSet<Integer>(); b.addAll( Arrays.asList( b)); // from an array variable b.addAll( Arrays.asList( 8, 9, 10)); // … Read more
You can do this: public void greaterCounter(List<Integer> input){ for (Integer i : input){ Integer count = 0; for (Integer j : input){ if (i < j) count++; } System.out.print(i+”,”+count+” “); } } 2 solved How to get count of number elements which are greater than current element in an arraylist [closed]
I made a working solution, please find below. public class TestClass { static ArrayList<ArrayList<Integer>> fullData = new ArrayList<>(); static ArrayList<ArrayList<Integer>> finalList = new ArrayList<>(); static int listTwocounter = 0; public static void main(String[] args) { int listOne[] = {1, 2, 3}; int listTwo[] = {7, 8, 9}; int listOneCombination = 2; int listOneSize = 3; … Read more
You are not permitted to mutate a list while you are iterating over it. Your l.remove(j) causes the list l to change, but you’re inside a for (Integer j : l) loop. 2 solved java+ ConcurrentModificationException forEach(enhanced) loop single thread [duplicate]
Let be a: public class MyClassWhithFourFields { String field1; int field2; Object field3; double field4; } Now you can declare a set with this template: Set<MyClassWhithFourFields> mySet = new HashSet<MyClassWhithFourFields>(); In your Set are your objects, which has 4 fields. If you want to declare a 2 dimension array, than what type should be? – … Read more
try this, for(int[] arr : parameters){ for(int item:arr){ System.out.println(item); } } 6 solved Integer array as type parameter in list in java [closed]
How about this? ArrayList<HashMap<String, HashMap<String, String>>> list = new ArrayList<>(); for (HashMap<String, HashMap<String, String>> m : list) { for (Map.Entry<String, HashMap<String, String>> e : m.entrySet()) { String key1 = e.getKey(); for (Map.Entry<String, String> me : e.getValue().entrySet()) { String key2 = me.getKey(); String value = me.getValue(); } } } Note that you really should be using … Read more
What is a simple algorithm / approach to store key-value (number-number) pairs *in disk* for quick access by key? [closed] solved What is a simple algorithm / approach to store key-value (number-number) pairs *in disk* for quick access by key? [closed]