Do you know about integer limits? A char value takes up 1 byte. A byte is usually 8 bits. To calculate the limit through the number of bits, the calculation is 2^n-1 meaning an integer with 8 bits has a range from 0 to 255 when unsigned. Since your variable is signed, it allocates a … Read more
Snippet 1 char a[200],*p; Defined a block of 200 characters ,a, and a pointer, p, to a block of one or more characters. gets(a); // cin.get(a,200); Read some user input into memory block a p=a; Points p at block a. p can now be used as a reference to the same thing as a strcpy(p,p+1); … Read more
The printf function has the following declaration: int printf(const char *format, …); The first argument must be a pointer to a char array, but any additional arguments can be of any type, so it’s not a compiler error if a format specifier mismatches the parameter (although it is undefined behavior). This still works however because … Read more
Array of char data type is called Sting. You can take a string’s input using scanf() and gets(). But if you use scanf(), the string will be input by pressing Space-bar or Enter. But if you use gets(), input will be given only by pressing the Enter key. Example 1: char s[100]; scanf(“%s”, s); Example … Read more
As per my understanding you are trying to assign space value in to char type .But the value you given is a string and trying to assign in to a char type .if u want to assign a space character do it by using ‘ ‘. char mychar=” “; //wont works because you are assigning … Read more
Since you already have a C string, just use strcmp. It will likely be faster than the s.compare method since you avoid the overhead of doing a conversion to std::string for both the original string and the string to compare to. if (strcmp(c, “hello”) == 0) { … solved fastest way to compare char* (C/C++)? … Read more
I copied the string into a new buffer. I struggled a bit to get this working. I don’t know whether it is what you wanted. #include <stdio.h> #include <stdlib.h> #include <string.h> int main(void) { int i, j, k; size_t count_comma = 0; size_t count_question_mark = 0; char question_mark[] = “question mark”; char comma[] = “comma”; … Read more
What are the repercussions of not using null termination in strings? Technically none, because C strings are – by definition – terminated by a null character: A string is a contiguous sequence of characters terminated by and including the first null character. So if it’s not properly terminated, it’s not a string. If you pass … Read more
The error is on this line: key[j]=words[index]; key is a std::string key; Therefore, key[j] is a char. words is a std::vector<std::string> words; Therefore, words[index] is a std::string. You cannot assign a std::string to a char. C++ doesn’t work this way. Your code is equivalent to the following: char a; std::string b; a=b; It is not … Read more
Instead of setting a character variable which is discarded, I assume you want to use this character to build a new String. StringBuilder sb = new StringBuilder(); for (char ch : dna.toCharArray()) { switch (ch) { case ‘A’: sb.append(‘T’); break; case ‘T’: sb.append(‘A’); break; case ‘G’: sb.append(‘C’); break; case ‘C’: sb.append(‘G’); break; } } String … Read more
The correct way to define and initialize your array is char Lookup[][3] = {“00”, “01”, “02”, “03”, “04”, “05”, “06”, “07”, “08”}; Each element of the array Lookup is itself another array of 3 bytes. Counting with the zero terminator, that’s enough space for strings 2 chars long. The number of elements in the array … Read more
charAt is zero based. You should use ab.charAt(0) if you use only a single char. Another good advice is to start method names with a lower case and use the camelCase format. 3 solved if char equals a letter then execute a code
Your function is declared to return char and you are returning an array of char. But even if you fix the return value which should be char * it’s still wrong because you should not return a local variable, instead pass the array as an argument to the function like this void n_zeroes(int n, char … Read more
A simple way to do it is to iterate over the string, that will give you each letter separately: alphabet = “abcdefghijklmnopqrstuvwxyz” for letter in alphabet: print(“a” + letter) solved Adding first character of a string to each of the other characters [closed]
I see a couple of issues. First, use the if..then..else construct or a switch for the several if..then statements. And, when you do a comparison to a char 10 is two char values so a simple == won’t work. You could convert it to an integer first, using atoi and then do a comparison, or … Read more