You’re on the right track. Just assign a value. int[,] matarix = new int[4, 5]; for (int x = 0; x < 4; x++) { for (int y = 0; y < 5; y++) { matarix[x, y] = VALUE_HERE; } } One recommendation I would make, would be to use Array.GetLength instead of hard coding … Read more
$str=”2015/2016-0 5 Gruuu 105 Fac Cience Comm 10073 Com Aud 103032 Tech Real TV 4 First Time feb First Quad 6.0 1 Lory Johnson, Nicholas 1334968 47107453A Cory Stein, Hellen Monster Cr. pie 5 a 3-2 08704 Iguan NewYork [email protected] [email protected] 617788050 Si 105 / 968 17/07/2015 0″; Get 6 numbers: preg_match(‘~\d{6}~’, $str, $matches); print_r($matches); … Read more
Change your code into: int main() { int N,count=0,i,j; scanf(“%d”,&N); int A[N]; … 0 solved Find the number of pairs (A[i], A[j]) such that i < j and A[i]**A[j] > A[j]**A[i]
// $type could be code or name function check_in_array($arr, $value, $type = “code”) { return count(array_filter($arr, function($var) use ($type, $value) { return $var[$type] === $value; })) !== 0; } 4 solved Check If In_Array (in Recursive Associative Array)
This is a very simple example as starting point showing only the relevant data. The example decodes the list array into a custom struct. the dt key is decoded into Date. Then it creates a DateComponents instance with noon in the current time zone and filters the dates. struct WeatherData : Decodable { let cod … Read more
That’s an invalid “object”. It is supposed to be an array with []. If that’s how your server is giving, you have to change the response there. In case, if you can’t do that, you may parse it right in JavaScript. var keyword = ‘{“coconut sugar”, “healthy and natural sweetener”, “low glycemic index sweetener”}’; keyword … Read more
If you set j = i then the minimum distance would be zero since you’d be computing the distance between a point with itself! If you set j = 0 the above would still apply, albeit with unnecessary duplicated comprisons, since you’d be including j == i. solved what happens when we change the value … Read more
string.Format(“[{0}]”, string.Join(“,”, array.Select(i => “{” + i.ToString() + “}”))); solved How to build an array of objects and then convert the whole array to an string [closed]
By char *stdnames[100]; you got an array of (pointers to char). The NEXT BIG QUESTION is Who will allocate memory for each of these pointers? A small answer would be – You have to do it yourself like below : stdnames[count]=malloc(100*sizeof(char)); // You may replace 100 with desired size or stdnames[count]=malloc(100); // sizeof(char) is almost … Read more
The functions are not being executed “automatically,” they’re being executed because you’re explicitly calling them: const arr = [ { ‘Some text’: this.f(‘a’) }, // ^^^^^^^^^^^−−−−−−−−−−−−−− here { ‘Some other text’: this.f(‘b’) } // ^^^^^^^^^^^−−−−−−−− and here ] The result of the above is an array with two objects in it, where the first object … Read more
while I’m pretty sure this is a homework assignment and well, you really should provide code of your own, at least try to, I found the thing amusing so I went ahead and gave it a try. I guess I’ll be downvoted for his and I probably do deserve it, but here goes anyway. What … Read more
You could use filter as follows from the parsed object: let obj = [{ “type”: 1, “key”: “123abc”, “data”: { “access”: “123456”, “data”: { “dataValue”: [{ “@attr”: { “@key”: “Fire” }, “@value”: “Flame” }, { “@attr”: { “@key”: “Water” }, “@value”: “Liquid” }, { “@attr”: { “@key”: “Earth” }, “@value”: “Stone” } ] } } … Read more
There is not enough information but I can guess you where you have made mistake. Your class Bookmark is not singleton class so,every time Bookmark() create new instance every time. that means it will create new bookmark object for every instance. What I suggest you is inside func func setBookmark(imageURL:String, title:String, description:String, summary:String, date:String, link:String) … Read more
Here You go: <?php $list = (object)[]; $list->egame = [ (object)[‘platform_name’=>’TT’, ‘game’=>(object)[(object)[‘game_name’=>’game1’, ‘info’=>’test1’],(object)[‘game_name’=>’game2’, ‘info’=>’test2’],(object)[‘game_name’=>’game3’, ‘info’=>’test3’]]], (object)[‘platform_name’=>’TG’, ‘game’=>(object)[(object)[‘game_name’=>’game4’, ‘info’=>’test4’],(object)[‘game_name’=>’game5’, ‘info’=>’test5’]]], (object)[‘platform_name’=>’TBIN’, ‘game’=>(object)[(object)[‘game_name’=>’game6’, ‘info’=>’test6’]]] ]; foreach ( $list->egame as $eg ) { foreach ( $eg->game as $game ) { echo “game: ” . $game->game_name . ” info: ” . $game->info . “<br>”; } } ?> Edit #1 … Read more
The usual pattern would be: public static final. That is a globally accessible and unmodifiable array reference: public class GravityV1 { public static final String[] PLANETS = { “Mercury”, “Venus”, “Earth”, “Mars”, “Jupiter”, “Saturn”, “Uranus”, “Pluto”}; public static final int[] DIAMETERS = { 4876, 12107, 12755, 6794, 142983, 120536, 51117, 49527, 2390}; public static final … Read more