For a correct answer I would need to know what you are trying or how, but a solution for that problem is as simple as <?php $array1 = array(“make”, “break”, “buy”); $array2 = array(“home”, “car”, “bike”); foreach ($array1 as $i => $value) { foreach ($array2 as $j => $value2) { echo $value.’ ‘.$value2.'<br />’; } … Read more
Here’s some code that works with recursion. It first finds all the options for the first query, and then recursively calls itself with the array of the objects with the same value for the given query, and at the deepest point, if there is no more queries, it returns the array of objects that meet … Read more
Define an nxn matrix A by a(i,j)=-1+2max(i,j) and b(j)=sum(j to n) a(i,j). Then test Naive-Gauss on this system (Matlab) solved Define an nxn matrix A by a(i,j)=-1+2max(i,j) and b(j)=sum(j to n) a(i,j). Then test Naive-Gauss on this system (Matlab)
Arrays can contain repeated values but, for obvious reasons, cannot contain repeated keys. array_combine will overwrite the value corresponding to each duplicate key it finds. Assuming that all your serial numbers are unique, a simple solution would be to swap round your array_combine to make the serial number the key: foreach (array_combine($serial, $make) as $number … Read more
Open your browsers javascript console (press F12) to see the output in the demo. jsfiddle demo var keys = [“key1″,”key2″,”key3”] var data = { “key1”: { “target”: “hostname”, “datapoints”: [ [12, 1.42472334E9], [13, 1.424723355E9], [14, 1.42472337E9]]}, “key2”: { “target”: “hostname”, “datapoints”: [ [15, 1.42472334E9], [16, 1.424723355E9], [17, 1.42472337E9]]} } //loop through the array named keys … Read more
Create a class student with variables for each of the fields: public class Student { public String strFirstName; public String strLastName; public String strMajor; public int intGPA; public int intUIN; public String strNetID; public String strAge; public String strGender; public static void Student(String strFirstName, String strLastName, String strMajor, int intGPA, int intUIN, String strNetID, String … Read more
You need to use a other array. <?php $lender = mysql_query(“Select * from lender where reference=”$reference””); $formated_lender = array(); while ($lenderrow=mysql_fetch_array($lender)) { $formated_lender = $lenderrow[“lender”] . ” ” . $lenderrow[“lenderref”] . ” ” . “£” . $lenderrow[“amount”]; } foreach ($formated_lender as $row) { echo $row . ‘<br />’; } Or, if you would just one … Read more
Here is the steps which you need to follow. Create a new array for merged objects Iterate the array Find the item which you’re looking for merge with the existing object to the filtered object append to new object done. let json = [{“id”:191,”warehouse_id”:24,”ingredient_id”:65,”expiration_date”:”2019-07-31″,”available_stocks”:7,”ingredient”:{“id”:65,”name”:”erg”,”SKU”:”1000064″,”default_unit”:{“id”:26,”name”:”Milliliter”},”purchase_price”:50}},{“id”:192,”warehouse_id”:24,”ingredient_id”:66,”expiration_date”:”2019-09-18″,”available_stocks”:33994,”ingredient”:{“id”:66,”name”:”gvf”,”SKU”:”1000065″,”default_unit”:{“id”:27,”name”:”Gram”},”purchase_price”:60}},{“id”:193,”warehouse_id”:24,”ingredient_id”:67,”expiration_date”:”2019-09-19″,”available_stocks”:43996,”ingredient”:{“id”:67,”name”:”fwefe”,”SKU”:”1000066″,”default_unit”:{“id”:26,”name”:”Milliliter”},”purchase_price”:70}},{“id”:52,”outlet_item_id”:null,”warehouse_item_id”:191,”ingredient_id”:65,”quantity”:7,”total_in_lowest”:0,”stock_on_hand”:0,”adjustment_price”:0,”soh_total_in_lowest”:0,”unit_price”:50,”difference”:0,”difference_in_lowest”:0}]; // new array after merging the objects let desiredArray = []; … Read more
You never call your method “forloop()”, that’s the reason why there’s nothing printed. NewbieJavaDeveloper’s answer is a good one. But if you want to pactice “method and return”, here is another answer: import java.util.Scanner;//import scanner so user can input class arrays { public static void main(String[] param) { String[] animals = arrays(); forloop(animals); System.exit(0); } … Read more
// take an array with some elements $array = array(‘a’,’z’,’c’,’b’); // get the size of array $count = count($array); echo “<pre>”; // Print array elements before sorting print_r($array); for ($i = 0; $i < $count; $i++) { for ($j = $i + 1; $j < $count; $j++) { if ($array[$i] > $array[$j]) { $temp = … Read more
That means that you try to access A[20] even though it doesn’t exist When i equals 19, the following line becomes a problem: A[i] = A[i + 1] + K; Use 19 insead of 20 in your loop and it should be fine. You need to decide what to do with A[19] though, as it’s … Read more
You may want to look into python’s list comprehension. arr = [int(arr_temp) for arr_temp in input().strip().split(‘ ‘)] Let me answer this with an example, suppose you input : 1 3 4 29 12 -2 0 the input function reads this as a string The strip function eliminates whitespace from both ends of the string, The … Read more
var songTimer = [0,12,49]; audio.addEventListener(“timeupdate”, function(){ if (songTimer.includes(audio.currentTime)) { // do something } }); solved javascript: How to trigger an if statement when a variable equals a number in an array? [closed]
You have your counter incrementing in the wrong place. int count = 0; foreach (string[] element in logBook) { Console.WriteLine (“#{0}: {1}”, count, element[0]); count++; // Increment after you print } solved C# How to start list count on 0 [closed]
The problem is likely that you’re starting your counter variables at 1, then using that as an index into the array, but array’s are zero-based in c# so you’re essentially skipping the first item at 0 and then trying to access an item that’s out of the bounds of the array. It’s also not accurate … Read more