[Solved] How to insert a single row data in a excel in c#?

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Indeed, this question already exists in stack overflow. By the way you can try this simple solution. public void loggeneration(DateTime datetime, string projectname, int totallines, int sum, int max) { // this is the variable to your xls file string path = @”c:\temp\log.xls”; // This text is added only once to the file. if (!File.Exists(path)) … Read more

[Solved] displaying images Gallery from assets/images

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The question is not clear, if you want to load a single image from assets, then you can do it this way. //read image from asset InputStream is = getAssets().open(“image.jpg”); // create a drawable Drawable drawable = Drawable.createFromStream(is, null); //find reference to your imageview and set drawable ImageView i=(ImageView)findViewById(R.id.image_id); i.setImageDrawable(drawable); 2 solved displaying images Gallery … Read more

[Solved] Change the version of ruby [closed]

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If you’re using Rbenv : https://makandracards.com/makandra/21545-rbenv-how-to-switch-to-another-ruby-version-temporarily-per-project-or-globally If you’re using RVM : https://rvm.io/rubies/default If you’re not using any of these: you should be using one of these. solved Change the version of ruby [closed]

[Solved] How to parse my JSON String in Android? [duplicate]

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Basically ‘[]’ this represent as JSONArray and ‘{}’ this represent JSONObject try { JSONArray jsonArray = new JSONArray(response); for(int i=0; i<jsonArray.length(); i++){ JSONObject jsonObject = jsonArray.getJSONObject(i); String id = jsonObject.getString(“id”); String name = jsonObject.getString(“name”); String surname = jsonObject.getString(“surname”); String il = jsonObject.getString(“il”); } } catch (JSONException e) { e.printStackTrace(); } 2 solved How to parse … Read more

[Solved] Cannot invoke split(String) on the array type String[] [duplicate]

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You can’t do split on a list, once you split the string then you have an array of all the IPs then you can check // 123.11.1.1, 123.1.1.12, 123.322.12.1 String[] list = merchant.getAllowed_ip_address().split(“,”); String ip = request.getRemoteAddr(); for (String allowedIP : list) { if (!ip.trim().equals(allowedIP.trim())) { // Not in list } } Also, you can … Read more

[Solved] How to read from textfile in java? [closed]

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What you want is to use a BufferedReader instance to read from the file, and parse each line that you get from it. For example: try { BufferedReader reader = new BufferedReader(new FileReader(“filename”)); String line; while ((line = reader.readLine()) != null) { // parse your line here. } reader.close(); // don’t forget to close the … Read more

[Solved] Why does my if else in this code doesn’t work? are we can not put if else inside another looping or is just my laptop that doesn’t work? [closed]

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Why does my if else in this code doesn’t work? are we can not put if else inside another looping or is just my laptop that doesn’t work? [closed] solved Why does my if else in this code doesn’t work? are we can not put if else inside another looping or is just my laptop … Read more

[Solved] JOINning two List-of-Lists to one [closed]

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Just use Pandas to convert your lists (income and Expenses) into Dataframes, merge them (in this case it’s basically an inner join on Year and Month) and then convert the Dataframe you get into a list of lists. df1 = pd.DataFrame(income, columns=[“Year”, “Month”, “X”]) df2 = pd.DataFrame(Expenses, columns=[“Year”, “Month”, “Y”]) joined = df1.merge(df2, on=[“Year”, “Month”]).values.tolist() … Read more