Kirat[ad_1] As you showed no effort in solving your problem, make effort in understanding this): echo count($check[‘offer’]) == count(array_intersect($check[‘basket’], $check[‘offer’])) ? ‘All present’ : ‘Nope’; 1 [ad_2] solved Check if values are present in an array based on another array [duplicate]
[ad_1] You can use the strncmp function to compare two strings up to a maximum number of characters. To start a comparison in the middle of a string, you would pass in the address of the array element to start the comparison at. For example: if (strncmp(&string1[4], &string2[4], 4) == 0) { printf(“characters 5 – … Read more
[ad_1] I’ve finally found the correct VBA I was looking for: ‘In your VBA window go to tools then references and add a reference to ‘Microsoft Word Sub Converter() Dim cnt As Integer, currfile As String Dim TrimFile As String, Path As String, FilesInPath As String _ , MyFiles() As String, Fnum As Long Dim … Read more
[ad_1] Could it be regarding mousePosition, which wasn’t declared in the code you provided? Also, what is windowText? Seems like we’re missing some more code… 1 [ad_2] solved Visual c++ identifier was not declared
[ad_1] You can do this: public void greaterCounter(List<Integer> input){ for (Integer i : input){ Integer count = 0; for (Integer j : input){ if (i < j) count++; } System.out.print(i+”,”+count+” “); } } 2 [ad_2] solved How to get count of number elements which are greater than current element in an arraylist [closed]
[ad_1] The code has undefined behavior, it may print 2 ! on your system, but it may do something entirely different on a different system, and indeed I don’t want to be flying a plane that runs it on its navigation system. Reformatting the code makes it a little more explicit: #include <stdio.h> int main() … Read more
[ad_1] The $redact operator of the aggregation framework is your best option: db.collection.aggregate([ { “$redact”: { “$cond”: { “if”: { “$lt”: [ { “$add”: [ “$b”, “$c” ] }, 5 ] }, “then”: “$$KEEP”, “else”: “$$PRUNE” } }}, { “$project”: { “_id”: 0, “a”: 1 } } ]) The logical condition is made via $lt … Read more
[ad_1] This function M will count groups of a value. It outputs a list of group occurrences in this format: [index of group, length of group]. It uses a flag m to keep track of in/out of group. If it’s out, it starts a new group occurrence, if it’s in, it increments the group length. … Read more
[ad_1] <a href=”intent:#Intent;action=your.example.namespace.CUSTOMACTION;package=your.example.namespace;component=your.example.namespace/.activity.YourActivity;S.extraValueName=WOW;end”> Launch App [ad_2] solved How to open android application if exists [closed]
[ad_1] Though I am not compleately sure what your question demands, but as far as i comphreanded it, True and False are being printed to your file, which is not the desired output? Well that’s because re.search returns a Match Object, For example: >>> search_string = ‘piiig’ >>> output = re.search(‘iii’, search_string) >>> output <_sre.SRE_Match … Read more
[ad_1] Here’s an issue I found: int boardcounter = 1; //… for (int j = 0; j < 3; j++) { board[i][j] = (char) boardcounter; boardcounter++; } The issue is that the cast (char) does not convert the int variable into a textual representation. The cast actually converts the integer to smaller sized integer variable. … Read more
[ad_1] Since you didn’t provide any code here and asked for the directions, so here you go. Lets assume your TextBox name is ‘textBox1‘ and there is some button beside it. On the click event of that button you should be querying your database for the customer names that matches the text inside your ‘textBox1‘. … Read more
[ad_1] You should change “.” to ‘.’. “” means string not a char [ad_2] solved Why same char is not equal [closed]
[ad_1] use a character class to split the values: /(-?[\d.]+)/ -? May start with a negative such as -123 [\d.]+ Has one or more numbers and decimals var string = “stuff 1.23! (456) 789 stuff -234”.split(/(-?[\d.]+)/); console.log(string) [ad_2] solved Javascript Array – Split string at numbers [closed]
[ad_1] blob=cv2.dnn.blobFromImage(cv2.resize(image,(300,300),1.0,(300,300),(104.0, 177.0, 123.0)) here is one closing bracket missing 0 [ad_2] solved I am writing a simple face recognition program I faced Syntax Error [closed]