[Solved] Is there a faster solution to solve this kind of job? [closed]
I’m not sure I understand your “job description”, but I think you want this: def find_matches(tuple_of_dicts, key_to_find): return [d for d in tuple_of_dicts if key_to_find in d] So: >>> tuple_of_dicts = ({18: None}, {10: None}, {16: None, 18: None, 5: None, 6: None, 7: None, 10: None}, {16: None}, {7: None}, {10: None}, {18: None}, … Read more