[Solved] Counting Values in R Vector

I like findInterval for these sorts of tasks: x <- c(1,2,3,20,21,22,40,41,42,60,61,62,80,81,82) table(findInterval(x,c(0,20,40,60,80))) 1 2 3 4 5 3 3 3 3 3 4 solved Counting Values in R Vector

[Solved] Masking inputs any field and values

if your output is acceptable on other field, this might be useful $(“#input”).on(“keyup”, function() { var input = $(this).val().split(“”) var res = $.map(input, (el, ix) => { return ix < 2 || ix > input.length – 3? el:”*” }) $(“#output”).html(res.join(“”)); }) <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <input type=”password” id=”input” /> <br><span id=”output”></span> 1 solved Masking inputs any field … Read more

[Solved] How to handle configuration properties in Java [closed]

Leverage standard Java Properties class. Create a properties file, i.e. conf.properties and load it. #conf.properties: key=value #code Properties conf = new Properties(); conf.load(new FileInputStream(new File(“conf.properties”))); conf.getProperty(“key”); // returns “value” solved How to handle configuration properties in Java [closed]

[Solved] How to scrape all product review from lazada in python

To do pagination use infinite while loop and #Check for button next-pagination-item have **disable** attribute then jump from loop else click on the next button. Code: from selenium import webdriver from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.support import expected_conditions as EC from selenium.webdriver.common.by import By import time driver=webdriver.Chrome(executable_path=”chromedriver”) driver.get(“https://www.lazada.sg/products/loreal-paris-uv-perfect-even-complexion-sunscreen-spf50pa-30ml-i214861100-s325723972.html?spm=a2o42.seller.list.1.758953196tH2Mn&mp=1”) review_csv=[] product_csv = [] rating_csv =[] date_review_csv … Read more

[Solved] R three dimensional arrays [closed]

So the way your question is posed is a bit sloppy, but an example of what you might be trying to do is to take the average of each 2000 x 22 array for each of the 3 of them. here is how this would be done: arr = array(1, dim=c(2000,22,3)) dim(arr) m = NULL … Read more

[Solved] String not valid as a datetime string – Convert “yyyyMMdd” to datetime [closed]

Introduction This article provides a solution to the problem of converting a string in the format of “yyyyMMdd” to a datetime object. This is a common issue encountered when dealing with date and time data, and can be solved using a variety of methods. This article will discuss the different approaches to solving this problem, … Read more

[Solved] Java logic operators [closed]

No, that would be a compilation error since it is parsing as if ((clickedButton == button0) || (button1) || (button2) … and buttons are not booleans. You must do: if (clickedButton == button0 || clickedButton == button1 … But an array would be much cleaner, instead of having nine separate button variables. Then you could … Read more

[Solved] How to get all months between two dates in PHP?

Just try with: $date1 = ‘2013-11-15’; $date2 = ‘2014-02-15’; $output = []; $time = strtotime($date1); $last = date(‘m-Y’, strtotime($date2)); do { $month = date(‘m-Y’, $time); $total = date(‘t’, $time); $output[] = [ ‘month’ => $month, ‘total’ => $total, ]; $time = strtotime(‘+1 month’, $time); } while ($month != $last); var_dump($output); Output: array (size=4) 0 => … Read more