This is what I came up with: First calculate the longest array. Then loop over the arrays, and loop over the items. Here’s a fiddle var a = [ ‘a1’, ‘a2’ ], b = [ ‘b1’, ‘b2’ ], c = [ ‘c1’, ‘c2’, ‘c3’ ]; var to2DArray = function(){ var maxLength = 0, arrays = … Read more
First of all, break your code up into sections and test each section. First, test that you have received the data correctly. A single error can stop the entire page from processing, so ensure you are receiving what you think you are receiving: $name = $_POST[‘name’]; $phone = $_POST[‘phone’]; $email = $_POST[’email’]; …etc… $zz = … Read more
I guess you need something like this: >>> from itertools import groupby #filter items that contain ’00:00′ >>> mylist = [x for x in mylist if x[-2] != ’00:00′ ] #now group lists based on the the second last item for k,g in groupby(mylist, key = lambda x 😡 [-2]): #find the min among the … Read more
As written by zaph in this answer, the following code should do what you want : NSData* bytesFromHexString(NSString * aString) { NSString *theString = [[aString componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] componentsJoinedByString:nil]; NSMutableData* data = [NSMutableData data]; int idx; for (idx = 0; idx+2 <= theString.length; idx+=2) { NSRange range = NSMakeRange(idx, 2); NSString* hexStr = [theString substringWithRange:range]; NSScanner* … Read more
val += line[i] == ” * “; is evaluated as val += (line[i] == ” * “); due to operator precedence. val will be incremented by 1 (true converts to an integral value of 1) if, and only if, line[i] compares true with ” * “, else it will stay the same. Finally #define endl … Read more
So, blah defines an instance field called label but does not initialise it public abstract class Blah { protected JLabel label; } BlahChildOne initialises the label from Blah public class BlahChildOne extends Blah { public BlahChildOne() { label = new JLabel(); } } BlahChildTwo does not initialises the label from Blah, so it is still … Read more
please find below working code import java.util.regex.Matcher; import java.util.regex.Pattern; public class Main { public static void main(String[] args) { String line = “This cat MAN-1243-23445 placed OK? This cat MAN-1243-23445 placed OK? This cat MAN-1243-23445 placed OK? This cat MAN-1243-23445 placed OK?This cat MAN-1243-23445 placed OK? This cat MAN-1243-23445 placed OK?”; String pattern = “(MAN-\\d{4}-\\d{5})”; … Read more
The Binding in the UserControl’s XAML should have the UserControl instance as its source object, e.g. like this: <ListView ItemsSource=”{Binding MessageList, RelativeSource={RelativeSource AncestorType=UserControl}}” /> Alternatively you could set x:Name on the UserControl and use an ElementName binding: <UserControl … x:Name=”self”> … <ListView ItemsSource=”{Binding MessageList, ElementName=self}” /> … </UserControl> Besides that you should usually not set … Read more
So, brutal but does work: =LEFT(A1,FIND(“,”,A1,FIND(“,”,A1,FIND(“,”,A1,1)+1)+1)-1) You can play with MID() and RIGHT() to get others…. See solved How to split a cell of many numbers by group of 3-3 in each next cells?
Why infinite loop appears to the script? There’s no infinite loop. For the input provided, it creates a hash with 239,517 elements, then dumps the hash. The output starts appearing almost immediately. Could you please tell me what does the $F[2]..$F[3] mean? In list context, if $F[2] and $F[3] are numbers, it returns a sequence … Read more
Try this: public static void main(String[] args) { for(int i=0;i<5;i++) { for(int j=0;j<5-i;j++) { System.out.print(” “); } for(int k=0;k<=i;k++) { System.out.print(“* “); } System.out.println(); } } Output: * * * * * * * * * * * * * * * Just for your knowledge System.out.println will print on a new line where System.out.print … Read more
I don’t think this loop is a good candidate for a foreach loop. If you were to do so, it would look something like this: var codeLengths = new[] { 4, 3, 2, 1 }; foreach (length in codeLengths) { if(xmlGenioCodes.SelectSingleNode(String.Format(“GenioCodes[Code =\”{0}\”]”, strCodeMX.Substring(0, length))) != null) { strCodeMXLayer = strCodeMX.Substring(0, length); break; } } EDIT … Read more
import csv one_year_reserved = { ‘australia-central’: 0.0097, ‘usgov-virginia’: 0.00879, ‘us-south-central’: 0.00731, ‘france-south’: 0.01119, ‘us-west’: 0.00719, ‘europe-north’: 0.00822, ‘asia-pacific-east’: 0.0097, ‘japan-east’: 0.00799, ‘west-india’: 0.00833, ‘united-kingdom-west’: 0.00685, ‘usgov-arizona’: 0.00879, ‘brazil-south’: 0.00982, ‘australia-east’: 0.00776, ‘us-west-2’: 0.00605, ‘asia-pacific-southeast’: 0.00776, ‘south-india’: 0.01005, ‘us-central’: 0.00731, ‘us-east-2’: 0.00605, ‘south-africa-west’: 0.01016, ‘canada-central’: 0.00674, ‘south-africa-north’: 0.00811, ‘canada-east’: 0.00685, ‘us-east’: 0.00605, ‘korea-south’: 0.00639, ‘united-kingdom-south’: 0.00685, … Read more
Your code already shows you making a new A() and a new B(). There is no AB(). By the nature of inheritance, a B is already an A; every B is also an A – just a more specific sub-type. A B = new AB(); says “declare B to be a new variable of type … Read more
The timedelta object doesn’t have hours property. Only microseconds, seconds and days. Use: myTime=”%02d:%02d:%02d.%06d” % (myTime.days*24 + myTime.seconds // 3600, (myTime.seconds % 3600) // 60, myTime.seconds % 60, myTime.microseconds) 3 solved How transform days to hours, minutes and seconds in Python