[Solved] Sending variable to PHP server from Android

[ad_1] For Android you can use HTTP Connection URL. An example is mentioned here How to add parameters to HttpURLConnection using POST URL url = new URL(“http://yoururl.com”); HttpsURLConnection conn = (HttpsURLConnection) url.openConnection(); conn.setReadTimeout(10000); conn.setConnectTimeout(15000); conn.setRequestMethod(“POST”); conn.setDoInput(true); conn.setDoOutput(true); List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair(“name”, “Chatura”)); OutputStream os = conn.getOutputStream(); BufferedWriter writer = new BufferedWriter( new … Read more

[Solved] I can not see text on the Image button? [duplicate]

[ad_1] you can’t use android:textfor the ImageButton. so just use a button and set background for it. For example: <Button android1:id=”@+id/btnShowLocation” android:layout_height=”wrap_content” android:layout_width=”wrap_content” android:layout_gravity=”center” android:padding=”10dp” android1:text = “@string/here_and_now” android:background=”https://stackoverflow.com/questions/13067637/@drawable/blue_button”/> 9 [ad_2] solved I can not see text on the Image button? [duplicate]

[Solved] How to choose range with php If condition [closed]

[ad_1] really just guessing here: <?php $i=23;//13,33,43,9999999993 if(substr($i,-1) == 3){ echo “there is 3”; } the code substr($i,-1) returns the last character of the string $i to cover 2 or 3 or 4 $i=24; if(in_array(substr($i,-1),array(2,3,4))){ echo “ends in 2 or 3 or 4”; } 0 [ad_2] solved How to choose range with php If condition … Read more

[Solved] Split a string in groovy

[ad_1] You can use the Java split(regex) method to achieve your first goal and then groovy syntactic sugar to help with the rest: def str = “,,,,,” def arr = str.split(/,/, -1) println arr.size() // 6 arr[0] = 1 arr[1] = 2 arr[2] = 3 println arr // [1, 2, 3, , , ] See … Read more

[Solved] Smtp authentification required [duplicate]

[ad_1] You need to tell the SMTP client that you will not be using your windows credentials to access the SMTP, so add smtpClient.UseDefaultCredentials = false; above this line of code smtpClient.Credentials = new NetworkCredential(“[email protected]”, “password”); Also, gmail doesn’t allow impersonation, so mailMessage.From = new MailAddress(“[email protected]”); will have no effect – the emails will still … Read more

[Solved] Differences with const keyword in C++

[ad_1] Here’s the most const example: class Foo { const int * const get() const {return 0;} \_______/ \___/ \___/ | | ^-this means that the function can be called on a const object | ^-this means that the pointer that is returned is const itself ^-this means that the pointer returned points to a … Read more

[Solved] Modulus of a very large number

[ad_1] BigInteger has the divideAndRemainder(…) method, one that returns a BigInteger array, the first item the division result, and the second, the remainder (which is what mod really does in Java). Update Including comment by Mark Dickinson to other answer: There’s a much simpler linear-time algorithm: set acc to 0, then for each digit d … Read more

[Solved] React: Warning each child in a list should have a unique key [duplicate]

[ad_1] It’s definitely an array key issue, but it seems you have unique alt attributes in each data set (array). <StyledHorizontalScrollList columns={columns}> {tunesTeasers.map(teaser => teaser.noTonieboxes ? ( <List key={teaser.alt} onClick={toggleModal}> <TeaserCard alt={teaser.alt} src={teaser.src} /> </List> ) : ( <StyledLink key={teaser.alt} to={teaser.link}> <TeaserCard alt={teaser.alt} src={teaser.src} /> </StyledLink> )} </StyledHorizontalScrollList> [ad_2] solved React: Warning each child in … Read more

[Solved] C language or programminng

[ad_1] You are not printing the upper right part. Change the for loops like this so that you print * for the remaining number if you subtract row from 7 for (row = 1; row <= 7; row++) { for (column = 1; column <= row; column++) putchar(‘*’); putchar(‘ ‘); for (column = row; column … Read more

[Solved] Catching error and user information

[ad_1] To solve this problem, you can use uncaughtExceptionHandler interface for this. public class ExceptionHandler implements UncaughtExceptionHandler{ Utils utils ; Context context; private final String LINE_SEPARATOR = “\n”; public ExceptionHandler(Context con) { // TODO Auto-generated constructor stub context = con; } @Override public void uncaughtException(Thread arg0, Throwable arg1) { // TODO Auto-generated method stub StringWriter … Read more

[Solved] JSON parsing in fragmant [closed]

[ad_1] It seems that your AndroidManifest.xml doesn’t give permission for your app to access the Internet. Your error log states: Permission denied (missing INTERNET permission?) Taken from The Android docs at http://developer.android.com/reference/android/Manifest.permission.html#INTERNET String | INTERNET | Allows applications to open network sockets. Add the following line to your AndroidManifest.xml to allow Internet access: <uses-permission android:name=”android.permission.INTERNET” … Read more