Month: October 2022

[Solved] Python slicing explained [duplicate]

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[ad_1] This will probably be deleted but here goes: First one is start at second position, head left as far as you can go. Second is start at rightmost, head left ending before -3. Third is start at-3 and head all the way to left. [ad_2] solved Python slicing explained [duplicate]

[Solved] Write a test that clicks on a date

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[ad_1] I’d suggest using some selector like this “(//td[contains(@class,’day’) and not(contains(@class,’disabled’))])[1]” This selector is using XPath – it matches any td element, which has ‘day’ string in its class atribute but doesn’t contain any ‘disabled’ string. The number in the end [1] is order of element selected, when multiple elements match the selector. Starting at … Read more

[Solved] C++ Using Object with pass function [closed]

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[ad_1] GradeBook::Grade is a non-static member function, it needs to operate on an instance of GradeBook. You can’t pass it in to a function expecting a plain function pointer. You could change TESTobj::SET to accept std::function objects, then wrap your member function in a lambda: void TESTobj::SET(std::function<void()> nu) void GradeBook::Set() { OBJ.SET([this](){Grade();}); OBJ.Test(); } [ad_2] … Read more

[Solved] array function C++

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[ad_1] bool equivalent(int a[], int b[], int n) { int i=0, j=0, count=0; // This condition fails immediately because the values are equal while (a[i] != b[j]) { // For this reason neither count nor j are incremented count++; j++; } for (int i=0; i<=n; i++) // This condition succeeds immediately because these values are … Read more

[Solved] User input integer list [duplicate]

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[ad_1] Your best way of doing this, is probably going to be a list comprehension. user_input = raw_input(“Please enter five numbers separated by a single space only: “) input_numbers = [int(i) for i in user_input.split(‘ ‘) if i.isdigit()] This will split the user’s input at the spaces, and create an integer list. 1 [ad_2] solved … Read more

[Solved] when reaching bottom the button should hide [duplicate]

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[ad_1] Demo jQuery var $window = $(window), $document = $(document), button = $(‘.button’); button.css({ opacity: 1 }); $window.on(‘scroll’, function () { if (($window.scrollTop() + $window.height()) == $document.height()) { button.stop(true).animate({ opacity: 0 }, 250); } else { button.stop(true).animate({ opacity: 1 }, 250); } }); [ad_2] solved when reaching bottom the button should hide [duplicate]

[Solved] Javascript accessing nested properties of an object literal

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[ad_1] The line el.setAttribute(key, [key]); tries to set the attribute to an array containing the key as its only entry (and thus will set href to “href” since the array will get coerced to string). You probably meant el.setAttribute(key, obj.att[key]); // ——————^^^^^^^ Live Example: function hoistNav() { const nav = []; nav[0] = {text: ‘HOME’, … Read more

[Solved] print empty asterisk triangle c

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[ad_1] you just need to think that first line should be filled with *. Second thing is first character of every line should be *. and last character should also be *. and in between you need to fill spaces. int main() { int n=6; for(int i=n-1;i>=0;i–) // using n-1, bcz loop is running upto … Read more

[Solved] C# – No overload for method “getal” takes 1 argument

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[ad_1] The error is saying there’s not method getal that has a string parameter. You’re invoking getal with txtNumber.text (string) as argument and the compiler is looking for a getal method with a string parameter and can’t find it. The existing getal method doesn’t take any parameters. public int getal(string x) { _a += _a; … Read more

[Solved] How to replace a substring with ( from a string

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[ad_1] This regex String a = “Want to Start (A) Programming and (B) Designing”; String b = a.replaceAll(“\\(“, “\n\\(“); System.out.println(b); results in Want to Start (A) Programming and (B) Designing Just escape the brackets with \\ and you’re fine. Edit: more specific, like mentioned below a.replaceAll(“(\\([AB]\\))”, “\n$1”); to match only (A) and (B) or a.replaceAll(“(\\(\\w\\))”, … Read more