You do not need to cast the int in your line number 1. Change this: x=int(10000) to this: x = 10000 Your code is fine, if the intention is to print the original value inside the loop and the last value i.e. 0 after the iterations, you need to print the current value afterwards. print(x) … Read more
First of all, 1<<10 is an expression that can be calculated at compile time, and it equals 1024. So your code is equivalent to #include <stdlib.h> int main() { int num=0; while(malloc(1024)) ++num; } So what it does is to allocate chunks of 1024 bytes of memory until it fails to do so. Each time, … Read more
You’re reusing the same string buffer. If you keep putting things into the same buffer without clearing it, you’re obviously going to get extraneous stuff from previous iterations. Simply declare the StringBuffer inside the while loop so that it is created on each iteration. Anyway, you should learn to use your debugger, instead of asking … Read more
You are shooting past your fixed-sized arrays due to a defective EOF test. Your loop should look more like the following: // also, don’t do preceding “usageFile >> … ;” while (true) { // you should also push as many of your charge/count variable declaration // in here as possible … // “readFile” is a … Read more
The problem is your use of while loops. while(note != 1) There is nothing in the body of those loops that change that condition. So everytime the loop goes “okay… is note not equal to 1?”.. that condition is always true. So the loop executes again. solved Stuck in infinite loop C#
The if condition checking must be done using == or === operator.Because = is used to assign something.So try this if($d == 2){ $dayznum = $dayznum2; } 3 solved PHP if($d=2) not working
this is b/c the while True does not end unless you use the keyword break wich breaks outside the loop and continues the code. the while True never ends the while loop while (condition): #code never ends until the condition is False, witch would never be true for the True condition. do your code should … Read more
Your while condition will be True if UserHand is any non-empty value, like ‘a’, or ‘3333’, because of UserHand or UserHand_Retry…. since or needs only one of these to be True and UserHand will be evaluated as True if it’s a non-empty string. while UserHand not in [“Rock”, “Paper”, “Scissors”]: Also, be careful with multiple … Read more
Firstly, You should not write in range(0,5) if you want to iterate through n numbers. Secondly, You do not need to write another while function. You use for loop or while loop for this question. Change for i in range(0,5): while i < 5: print(i ** 2) i += 1 break to for i in … Read more
Try use jquery, the below example is for random numbers. <script> var id = window.setInterval(function(){randomNumber();},1000); function randomNumber() { var rand = Math.floor(Math.random()*6); //Do whatever you want with that number $(‘#holder’).html(rand); } </script> <!DOCTYPE html> <html> <head> <script src=”http://code.jquery.com/jquery-1.9.1.min.js”></script> <meta charset=utf-8 /> <title>Random Number</title> </head> <body> <div id=’holder’></div> </body> </html> For random text var names = … Read more
you can do the following: explanation for the code: Square is formed of 2 equal sides, so in order to draw the square using *, you will think of it like a matrix you need a loop to draw the rows and another loop to draw the columns, and both loop has upper limit which … Read more
this is a suitable time to utilize the do while loop the way it works is it will execute the statement within the block without evaluating any conditions and then evaluate the condition to determine if the loop should run again this is what your program could look like #include <iostream> using namespace std; int … Read more
Firstly, you can simply write while True: Instead of a = True while a: Secondly, you don’t use total or t anywhere. You can delete them. Thirdly, if x has to belong to [a, b], you can write if a <= x <= b: Fourthly, you can use else statement instead of negation of if. … Read more
Try this one: counter = 0 while Amzn > 1000: counter+=1 print(“Watch”) Amzn = Amzn – (Amzn*.0103) else: print(“buy”) print(counter) 1 solved How can I count the outputs of a while loop in python? [duplicate]
I think you need to re-query res2 inside the outer loop, or at least reset the pointer. The second time through the outer loop you have nothing left in res2, since you’ve already reached the end In addition, with would be a lot more efficient if you setup the res2 query inside the outer loop … Read more