Presumably MAC_ADRESSES is not an array of pointers. NULL is a pointer (normally (void *)0 in C), so you can’t assign it to a non-pointer variable. Edit: Since your definition is char MAC_ADRESSES[MAX_LINES][100], you have a 2D array, not an array of pointers. You can’t store NULL in this array. You can wipe out a … Read more
The simple answer that won’t help you much is that this is done for backwards compatibility with C, that has exactly the same syntax to define variables. The rationale for that design would have to come from the creators of C, and I don’t really know it. What I do know is that most coding … Read more
By doing ((aStr = $(printf %03d $a))), you are destroying again the careful formatting done by printf. You would see the same effect if you do a (( x = 005 )) echo $x which outputs 5. Actually the zeroes inserted by printf could do harm to your number, as you see by the following … Read more
Try to compile you code with a serious ANSI C compiler, from C89 to C11, and you will get the same error: Test.c(9): error #2168: Operands of ‘=’ have incompatible types ‘double *’ and ‘int *’. Test.c(11): error #2168: Operands of ‘=’ have incompatible types ‘double *’ and ‘char *’. Test.c(13): error #2168: Operands of … Read more
c++ Making a code that displays equations and keep getting the “expression must have integral or unscoped enum type” error solved c++ Making a code that displays equations and keep getting the “expression must have integral or unscoped enum type” error
From cppreference: An enumeration is a distinct type whose value is restricted to one of several explicitly named constants (“enumerators”). The values of the constants are values of an integral type known as the underlying type of the enumeration. So an example of an enumerated type is any type you might declare using the enum … Read more
Introduction Solution The error you are getting is likely due to the fact that you are trying to assign a value to a variable that is not of an integral or unscoped enum type. To fix this, you will need to make sure that the type of the variable you are assigning a value to … Read more
Introduction Enumerated types, also known as enum types, are a special type of data type in C++. They are used to define a set of named constants, which can be used to represent a set of related values. Enumerated types are useful for representing a set of related values that can be used in a … Read more
Based on my understanding you want to check if the type is a list and if the list’s elements is type X. You can do the following: var type = (new List<int>()).GetType(); if (type.GetInterface(“IList”) != null && type.IsGenericType && type.GenericTypeArguments.Length == 1 && type.GenericTypeArguments[0] == typeof(int)) Console.WriteLine(true); //Outputs True 3 solved Item type from a … Read more
In ruby all things like numbers, strings are objects. We don’t need to specify any datatype to variables. example- <%= f.radio_button(:A_Impact_Value,1) %> so here A_Impact_Value datatype can be integer,boolean . solved Ruby On Rails — Check boxs , Dropdowns , Radio buttons [closed]
Since you already determined the type (typeof(Jedi)) you are almost there. The Type class has two properties: IsPublic and IsNonPublic. You can use them to determine the access mode of your types: public class Public { } internal class Program { private class Private { } [STAThread] private static void Main(string[] args) { Private pr … Read more
Read up on your Visual Basic for Applications data types here on MSDN Code example for the basic numeric types: Sub Some_sub() Dim a As Double Dim b As Long Dim c As Integer Dim d As Single a = 0.02 b = 0.02 c = 0.02 d = 0.02 Debug.Print a ‘output: 0.02 Debug.Print … Read more
The biggest value an int can hold is 2,147,483,647. Change the variables to unsigned long long, which can hold a maximum of over 18,446,744,000,000,000,000. (You’ll need to use %llu to read in/out unsigned long long variables) Also, always validate inputs, this would have hinted at the issue. if(scanf(“%d”, &a) < 1) { //if we read … Read more
Since the pointer returned by malloc() is sufficiently well aligned to be used as a pointer to any type, you could (but probably shouldn’t) use: assert(sizeof(float) <= 10); void *data = malloc(10); char *str = data; strcpy(str, “123.4”); float *vp = data; *vp = strtof(str, NULL); …use *vp… free(data); And now you can use *vp … Read more
Looking at your code the class Result is not a list which I think you are trying to call with List()? not sure.. To create a List<> you can do it multiple ways see below on a few options. Try these in your Main method. List<string> stringList = new List<string>(); //creates a List<string> called stringList … Read more