[ad_1] A simple way can be to split the string on each character and join the parts using space as the delimiter. Demo: public class Main { public static void main(String[] args) { String s = “AB”; s = String.join(” “, s.split(“”)); System.out.println(s); } } Output: A B [ad_2] solved Add space between two characters … Read more
[ad_1] I figured the problem that your code is not able to compare the last character.It expects a space after the last character so that it can compare the last character since java doesn’t use null character terminator for string termination.I have emulated the same code using Scanner class as I was having some trouble … Read more
[ad_1] I think I see your problem: you’ve mistaken the meta-syntax of documentation for Python syntax. When a document describes a command with optional fields, brackets denote the option parts. This description style is at least 45 years old, dating back to the days when IBM drove all things computer in the western hemisphere. For … Read more
[ad_1] You’ve already generated a random number here: new Random().nextInt(names.length) You can use this random number to access an element in the names array. int randomNumber = new Random().nextInt(names.length); String option = names[randomNumber]; // here is the important bit! Now you can print option out! System.out.println(“You are going to eat ” + option); 0 [ad_2] … Read more
[ad_1] No that’s not really a good way. If you just want the numbers a numbers, i.e. as normal int values, then use the “%d” conversion operator instead, and have your variables be normal int variables, which you then pass to sscanf using the address-of operator &. As in int num1; int num2; int num3; … Read more
[ad_1] Change for(x = 0; x < num +1; x++) to for(x = 0; x < num; x++) Also you might have meant for(boolean guessed = false; guessed == true;) // notice == instead and then setting this flag to true within this(outer) for loop. [ad_2] solved ava.lang.StringIndexOutOfBoundsException: String index out of range: 9 at … Read more
[ad_1] A simple solution is by trying all possible substrings from left to right (i.e. starting from indices i=0 to n-k), and comparing each to the next substrings (i.e. starting from indices j=i+1 to n-k). For every i-substring, you count the number of occurrences, and keep a trace of the most frequentso far. As a … Read more
[ad_1] Well, since you want to use String numbers, you will have to wrap them in quotations, but your sorting can be much more readable. I would suggest the following String[] numbers ={“-100”, “50”, “0”, “56.6”, “90”, “0.12”, “.12”, “02.34”, “000.000”}; List<BigDecimal> decimalList = new ArrayList<>(); for(String s: numbers){ decimalList.add(new BigDecimal(s)); } Collections.sort(decimalList); Collections.reverse(decimalList); // … Read more
[ad_1] This is useful—it does the same thing as DateTime.Parse, BUT DOES NOT THROW ANY EXCEPTIONS It returns true if the parse succeeded, and false otherwise. protected void Foo() { // Use DateTime.TryParse when input is valid. string input = “2014-02-02T04:00:00″;//”2014-02-02”; DateTime dateTime; if (DateTime.TryParse(input, out dateTime)) { lblresult.Text = dateTime.ToString(); } else { lblresult.Text … Read more
[ad_1] String ouput = String.format(“%.2f + %.2f = %.2f”,x,y,total); System.out.println(output); will give you the output with 2 decimal places or you can use DecimalFormat as well. 0 [ad_2] solved How can I format this String with double x,y,total to two decimal places. output = (x + ” + ” + y + ” = ” … Read more
Introduction [ad_1] This article will provide a solution to formatting a String with double x, y, and total to two decimal places. The output of the String should be in the form of (x + ” + ” + y + ” = ” + total). We will use the DecimalFormat class to achieve this. … Read more
[ad_1] I have to admit this is a bit excesive use of .replace() but there isn’t much to work with: $mystring= ” S: Title = test S: Title = test2 S: Title = test3 S: Title = test4 TE: 2019-01-19T00:00:00Z TE: 2019-01-20T00:00:00Z TE: 2019-01-22T00:00:00Z TE: 2019-01-23T00:00:00Z ” $MyString.trim().replace(” S: Title = “,”,”).replace(“T00:00:00Z TE: “,”,”).replace(“TE: “,””).replace(“S: … Read more
[ad_1] You can use regex and Pattern matching to extract it, e.g.: String s = “If this is good and if that is bad”; Pattern pattern = Pattern.compile(“if(.*?)is”); Matcher m = pattern.matcher(s); if(m.find()){ System.out.println(m.group(1).trim()); } 3 [ad_2] solved Extracting a substring based on second occurence using Java – substringBetween() function [closed]
Introduction [ad_1] The substringBetween() function in Java is a useful tool for extracting a substring based on the second occurrence of a given character or string. This function is part of the Apache Commons Lang library, and it can be used to extract a substring from a larger string. This tutorial will explain how to … Read more
[ad_1] def repeat_middle(text): a, b = divmod(len(text) – 1, 2) middle = text[a:a + b + 1] exclamations=”!” * len(middle) return ‘{}{}{}’.format(exclamations, middle * len(text), exclamations) >>> print repeat_middle(“abMNcd”) !!MNMNMNMNMNMN!! >>> print repeat_middle(“abMcd”) !MMMMM! [ad_2] solved Repeating Characters in the Middle of a String