[ad_1] I solved my problem guys.. here is my sample code.. it works wel.. dynamic stuff = JsonConvert.DeserializeObject(res); int id=stuff.id; 4 [ad_2] solved how to split single data from string..? [closed]
[ad_1] You could get the length of the list of items after splitting: len(my_long_string.split(‘;’)) Alternatively, count the number of semicolons and add one: my_long_string.count(‘;’) + 1 The latter is probably faster if you don’t need to know what the items are, but only how many items there are. len is a function that returns the … Read more
[ad_1] as pointed out by @Delgan, it can be done directly via d1 = dict(keyval.split(“, “) for keyval in a_list) without the inner nesting 🙂 older approach which were not really correct :- d = [a.split(‘,’) for a in a_list] d1 = {key: val for key,val in d} or d1 = {key: val for key,val … Read more
[ad_1] $String1 = ‘ABC*WELCOME*CDF’; list( ,$myString, ) = explode(‘*’,$String1); echo $myString; 2 [ad_2] solved How to split a string between two delimiters in php [closed]
[ad_1] If we can guarantee that the String to parse is always defined in a canonical way, so that is defined as lat+long ALWAYS, then using regex will be the easiest way: Example: String latLong = “lat/lng: (55.94569390835889,-3.190410055779333)”; Pattern patte = Pattern.compile(“-?[0-9]+(?:.[0-9]+)?”); Matcher matcher = patte.matcher(latLong); while (matcher.find()) { System.out.println(Double.parseDouble(matcher.group())); } [ad_2] solved Splitting a … Read more
[ad_1] You can go with regex in here like this: Regex rgxData = new Regex(“([0-9 ]+)([a-zA-Z]+)”); Match mData = rgxData.Match(input); string sr = mData.Groups[1].Value.Trim(); string quota = mData.Groups[2].Value.Trim(); This will result in: input = “153 81 2612GEN”; SR: 153 81 2612 Quota: GEN input = “153 81 1 1 1 1 1 1 ABCDE”; SR: … Read more
[ad_1] you can use the following Regex To extract no from your string string input =”Example123456.csv”; input = Regex.Replace(input, “[^0-9]+”, string.Empty); the output will be 123456 [ad_2] solved C# Split String before the first number
[ad_1] You can solve this problem using a regular expression and NSRegularExpression. Construct a pattern which matches the text between brackets. For example the pattern @”\\[([^]]*)]” matches an opening bracket \\[ – the backslash is required to treat the bracket as a literal character, zero or more characters except a closing bracket [^]]*, groups that … Read more
[ad_1] I assume that your expected output is bye see you.If I understood correctly then following methods can be used to get the desired output: In this string splits into an array(splits()) with delimiter ” ” and find index of bye (j)and you(k) in the array then using a for loop to get strings in … Read more
[ad_1] You can use this: string test = “200| Άρχισε ξανά| Start again| test | test? |201,202,203,204 |list | picture]”; int pos = -1; for ( int i = 1; i <= 5; i++) { pos = test.IndexOf(‘|’, pos + 1); if ( pos == -1 ) break; } string result = “”; if ( … Read more
[ad_1] Here’s a different approach that handles nulls and does not risk altering any data. It uses a with clause to break down the data by the delimiters, ending up with splitting on the commas. ASSUMPTION: Steps have already been taken to ensure that the data has already been scrubbed of the delimiter characters (commas … Read more
[ad_1] This should work. As mentioned in the comments. a is not a string but an array. So you need to iterate over it to call the split() method on it’s containing strings String s = “How are you?” String[] a = s.split(“\\s”); for(String s2 : a){ String[] a2 = s2.split(“”); // do your stuff … Read more
[ad_1] use a character class to split the values: /(-?[\d.]+)/ -? May start with a negative such as -123 [\d.]+ Has one or more numbers and decimals var string = “stuff 1.23! (456) 789 stuff -234”.split(/(-?[\d.]+)/); console.log(string) [ad_2] solved Javascript Array – Split string at numbers [closed]
[ad_1] Scala string split method uses regular expression, { is a special character in regular expression which is used for quantifying matched patterns. If you want to treat it as literal, you need to escape the character with , \\{: val s = “””word, {“..Json Structure…”}””” // s: String = word, {“..Json Structure…”} s.split(“, \\{“) … Read more
[ad_1] there is a method in String class that can help you convert it, but you should give this method the regex , in your case regex is “,” you can use this method to convert it: public String[] convertToArray(String str, String regex){ return str.split(regex); } String[] str = convertToArray(str, “,”); [ad_2] solved String to … Read more