[Solved] Matlab spilt one txt file to several files

This solution below should do the trick (at least it does for the simplified version you put above. fi = fopen(‘myFile.txt’,’r’); fileCount = 1; fo = fopen([‘output’,num2str(fileCount),’.txt’],’w’); header = fgets(fi); fprintf(fo,header); tline = header; first = true; mark_index = 8; while ischar(tline) if (~first) values = cell2mat(textscan(tline,’%f ‘)); if values(mark_index) == 1 fclose(fo); fileCount = … Read more

[Solved] How to split a string if any chracter is found in java

You can use String‘s methods replaceAll and split together here. String one = “show ip interface brief | include 1234**\n Gi1/23.1234 xxx.225.xxx.106 YES manual up up”; String[] tokens = one.replaceAll(“[^\\n]+\\n\\s*”, “”).split(“\\s+”); System.out.println(Arrays.toString(tokens)); Output [Gi1/23.1234, xxx.225.xxx.106, YES, manual, up, up] solved How to split a string if any chracter is found in java

[Solved] How to delete first text? (c#)

If you have dynamic separators like this, String.Split is not suitable. Use Regex.Split instead. You can give a pattern to Regex.Split and it will treat every substring that matches the pattern as a separator. In this case, you need a pattern like this: \d+\. |1|2|3|4 | are or operators. \d matches any digit character. + … Read more

[Solved] I want to display words separate from a sentence

sentence = “Get a sentence from the user and display it back with one word per line.” for character in range(len(sentence)): if sentence[character] == ‘ ‘ or sentence[character] == ‘.’ or sentence[character] == ‘,’: print(“”) else: print(sentence[character], end=”) OUTPUT: Get a sentence from the user and display it back with one word per line solved … Read more

[Solved] Removing all occurrences of any characters in the word ‘dust’ in the string [closed]

Introduction This article will discuss how to remove all occurrences of any characters in the word ‘dust’ from a given string. We will look at various methods of doing this, including using regular expressions, looping through the string, and using the replace() method. We will also discuss the advantages and disadvantages of each approach. Finally, … Read more

[Solved] Removing all occurrences of any characters in the word ‘dust’ in the string [closed]

Use a regular expression. import re result = re.sub(r'[dust]’, ”, string) The regexp [dust] matches any of those characters, and all the matches are replaced with an empty string. If you want to remove only the whole word dust, with possible repetitions of the letters, the regexp would be r’d+u+s+t+’. If only u can be … Read more

[Solved] C# array string names change content order

First, let’s elaborate rules: One part “John” -> “John” (do nothing) Two parts “John Smith” -> “Smith, John” (last, first) Three+ parts “John Peter Jack Smith” -> “Smith, John P. J.” (last, first, other in order as single letters) Having these rules we can implement a simple reordering: private static String ReOrderNamesParts(string name) { if … Read more

[Solved] Separate object string when it’s an uppercase letter c# [duplicate]

Is Regex required? Here’s linq. edit: added a regex option as well since that was requested. ([a-z])([A-Z])”, “$1 $2”) matches lowercase letter and then uppercase letter and returns the matches as $1 and $2 respectively w/ a space in between. Note: this won’t work if you have accented characters like É, is that needed in … Read more

[Solved] PostgreSQL query to split based on Strings & Concatenate them into new individual columns

Use string_to_array to split the string into multiple elements that can be accessed individually: select rules[1] as rule_1, rules[2] as rule_2, rules[3] as rule_3, rules[4] as rule_4, rules[5] as rule_5, rules[6] as rule_6 from ( select string_to_array(rules, ‘|’) as rules from rulebook ) t 1 solved PostgreSQL query to split based on Strings & Concatenate … Read more