You can use the indices method of the slice to generate a tuple that can be passed to range. You need to know the length of your instance though. For example: >>> sl = slice(2) # or wherever you get that from >>> length = 100 >>> list(range(*sl.indices(length))) [0, 1] 5 solved How to transform … Read more
>>> from itertools import groupby >>> from operator import itemgetter >>> list1 [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] >>> list2 [0, 0, 3, 4, 5, 0, 0, 8, 9, 0] >>> [[e[0] for e in v] for k,v in groupby(((a ,b, a==b) for a,b in zip(list1, list2)), itemgetter(2)) if k] [[3, … Read more
There’s no built-in method what you’re looking for (merging slices). However, you can use append method like: s.setGrade(append([]int{80}, s.Grade[1:]…)) If you had to update two grade ints then you could have done: s.setGrade(append([]int{80,95}, s.Grade[2:]…)) 1 solved Index slice within Main func when using setGrade()
Introduction Index slice within Main func when using setGrade() is a common problem encountered when working with arrays in programming. It can be solved by using a combination of indexing and slicing techniques. Indexing is used to access individual elements of an array, while slicing is used to access a range of elements. By combining … Read more
Yes you can… it is built right into photoshop and part of “save for web” options… HOWEVER though this exists, it is VERY limited in what it can do and should really be used as a springboard from which to jump of from. You can set it up to export the document as a CSS … Read more
If you model your JSON object with a struct and you unmarshal into a value of that, then you don’t need those ugly indices and type assertions, you can simply refer to struct fields. Note that you don’t have to be afraid of the response being complex, you only need to model the parts you … Read more
You could write tokenize which consumes your text input and produces a stream of tokens – const input = [ ‘7’, ‘3’, ‘+’, ‘6’, ‘x’, ‘8’, ‘+’, ‘5’, ‘4’, ‘x’, ‘2’ ] function* tokenize (es) { let r = 0, n for (const e of es) { switch (e) { case “+”: case “x”: yield … Read more
Let’s say that you pass the string XII to your function. That makes len(s) 3, which means that the body of your loop would (if the panic didn’t occur) execute 4 times (when i is 0, 1, 2 and 3 since your condition is i <= len(s). On the iteration where i is 2 (i.e. … Read more
Well, for this example, you could use list comprehension with slicing. a = [[1, 2], [1, 2, 3], [1, 2, 3, 4]] b = [x[1:] for x in a] 0 solved Remove the first items in a list of lists – make a copy instead of modifying in-place
Here slice nums[:i] is created by slicing a bigger array nums. This leads to it having enough capacity to extend in place. So an operation like append(nums[:i], nums[i+1:]…) causes the elements in nums getting overridden by elements from nums[i+1:]. This mutates the original array and hence the behaviour. As suggested by @icza the concept has … Read more
With the slice method you are just extracting a ‘slice’ of the array starting from here (begin) to there (end). To implement the slice function yourself try something like this: function newSlice(array, begin, end) { let tempArray =[]; if(end===undefined || end > array.length) end = array.length; for (let i = begin; i < end; i++) … Read more
Add a print(N) line after all the N+= lines, and try various Z arrays. For example Define a small z with a block of 1s in the middle: In [29]: z = np.zeros((10,10),int) In [31]: z[4:6,4:6]=1 In [34]: z[4:8,5]=1 In [35]: z Out[35]: array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, … Read more
What you did is clean and fast enough. What you could improve on it is to pre-allocate the slice and fill it using a for.. range loop like this: s := make([]int, 5) for i := range s { s[i] = rand.Intn(100) } The math/rand package also has a rand.Read() function which fills a slice … Read more
package main import “fmt” func main() { //create a map m := map[int64]int64{512: 8, 513: 9, 234: 9, 392: 0} //create a slice to hold required values s := make([][]int64, 0) //range over map `m` to append to slice `s` for k, v := range m { // append each element, with a new slice … Read more
Since the map key type is an array, the assignment: for k,_ := range ans { will rewrite k for every iteration. This will rewrite the contents of the array k. The slice k[:] points to k as the underlying array, so all the slices with k as their underlying array will be overwritten as … Read more