What you shared is not valid python code. Here is an example of code that will accomplish what you are asking: # define function: def CalculateMortgage(p, i, n): # calculate numerator: numerator = p * (i *(1+i) ** n) # calculate denominator: denominator = ((1+i) ** n – 1) # calculate mortgage: mortgage = numerator/denominator … Read more
When you call dict() with an iterable it expects that iterable to return pairs of values, that it can use as keys and values to create the dict. So, these examples are all valid: dict([(‘key’, ‘value’), (‘other_key’, ‘other_value’)]) dict([‘ab’, ‘bc’, ‘dd’]) # ‘ab’ is pretty much equivalent to a list [‘a’, ‘b’] dict([[‘a’, 1], [‘b’, … Read more
You can do this with whatever class you want, but here’s a quick example using namedtuple >>> from collections import namedtuple >>> Point = namedtuple(‘Point’, ‘x y’) >>> def my_func(): return Point(1, 9) >>> my_func().x 1 This code is completely useless though 8 solved function returning an object in python [closed]
Use groupby (http://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.groupby.html) Assume your input is saved in a pandas Dataframe (or equivalently save it into csv and read it using pandas.read_csv). Now you can loop over the groups with same S.No values with the following: output = {} for key, group in df.groupby(‘S.No.’): # print key # print group output[key] = {} output[key][‘Details’] … Read more
I am coding a game where i have a list of list of buttons and i wish to pass a on click command based on there coordinate in the grid solved I am coding a game where i have a list of list of buttons and i wish to pass a on click command based … Read more
Consider a simplified example where your line of code >>> response=conn.getresponse() has retrieved the response from the server and saved it as an HTTPResponse object, and when you .read() the response you see a JSON string like this >>> responseData = response.read().decode(‘utf-8’) >>> responseData ‘{“day”: “Thursday”, “id”: 3720348749}’ You can use Python’s built-in JSON decoder … Read more
The code loops through word with a step size of 3 and groups every 3 consecutive words. Let’s say word = [1, 2, 3, 4, 5, 6, 7, 8, 9] Over the course of the loop, i will be = 0, 3, 6 To grid, you append word[0:3],word[3:6],word[6:9] So grid will have in it [[1,2,3],[4,5,6],[7,8,9]] … Read more
It is not very hard to write an expression for this. >>> import re >>> re.findall(r’@(\S+)’, ‘ I want to tell @susan and @rick that I love you all’) [‘susan’, ‘rick’] Or use \w which matches any word character. >>> re.findall(r’@(\w+)’, ‘ I want to tell @susan and @rick that I love you all’) [‘susan’, … Read more
To sum the values, you can loop over the data using .items(), will return the key with its associated value at each iteration: s = {‘A’: [3, 4, 7], ‘B’: [4, 9, 9], ‘C’: [3, 4, 5], ‘D’: [2, 2, 6], ‘E’: [6, 7, 9], ‘F’: [2, 4, 5]} new_dict = {} for a, b … Read more
There needs to be a body to those empty if/elif statements Example (python 2 style): if computerChoice == 0: print ‘Something needs to be done here’ elif computerChoice == 1: print ‘Something needs to be done here too’ elif computerChoice == 2: print ‘And something needs to be done here, too’ Obviously replace those print … Read more
If it was for i in range(1,10): if space_check(board, i): return False else: return True then after the first iteration in the for loop the function would return. This would not lead the the expected behaviour. Currently, you check every space, and not just the first one 9 solved Are booleans overwritten in python?
The problem is, that your value i is an integer and the print-function takes a string as parameter. Therefore you need to cast your variable using the str() function. Your code should look like this: for i in range(999999999999999): print (“sending messages no.” + str(i)) Now, I encourage people to learn Python and so I … Read more
it allows to define a criterion which replaces the < comparison between elements. For instance: >>>l = [“hhfhfhh”,”xx”,”123455676883″] >>>max(l, key=len) ‘123455676883’ returns the longest string in the list which is “123455676883” Without it, it would return “xx” because it’s the highest ranking string according to string comparison. >>>l = [“hhfhfhh”,”xx”,”123455676883″] >>>max(l) ‘xx’ 2 solved What … Read more
Check the documentation https://docs.python.org/3/library/stdtypes.html#string-methods https://docs.python.org/3/library/stdtypes.html#str.index Build your code around the method: # characters to look for in a list (string would work as well) vowels = [“a”,”i”,”o”,”u”,”e”,”y”] # a function (method) def vowel_indices(word): # prepare empty list to collect the positions in hits = [] # test every of your vowels for vowel in vowels: … Read more
Since your question does not clearly state that: This anwer assumes that the entries in all list should be sorted afterwards and that each number is unique within each sublist. You can reach this as follows: numbers = [[50, 100],[100, 130],[20, 50, 100, 130]] unique = sorted({n for l in numbers for n in l}) … Read more