If you want to cycle the list elements, you can use itertools.cycle. We can call next twice on each iteration to get two numbers at a time from the iterator. from itertools import cycle a = cycle([0,1,2,3,4,5,6]) for _ in range(10): print(f”{next(a)} – {next(a)}”) Output: 0 – 1 2 – 3 4 – 5 6 … Read more
This can be put into one line in several ways. Without changing your code you could just remove the newline and indent: with open(‘output.txt’, ‘w’) as f: for item in winapps.list_installed(): print(item, file=f) Or just using unpacking and print formatting: with open(‘output.txt’, ‘w’) as f: print(*winapps.list_installed(), sep=”\n”, file=f) Which can also be done in one … Read more
This isn’t elegant, but you could strip line endings, then replace the spaces and tabs: askuser = askuser.strip().replace(‘ ‘,”).replace(‘\t’,”) solved How do I remove all white space in any given input? [closed]
You were almost there s = “hello” out = “” for letter in s: out += letter print(out) for letter in out: out = out[:-1] print(out) Output: h he hel hell hello hell hel he h solved How to make a substring pyramid psuedocode with words on Python? [closed]
import re FILEPATH = “./file.txt” def main(): pattern = re.compile(“‘serial_number\’\: u\'(.*?)\'”) with open(FILEPATH, ‘rU’) as f: print(pattern.findall(f.read())) if __name__ == “__main__”: main() 4 solved Extract string from text file using python [closed]
When working with dates and times, it is almost always best to convert the date first into a Python datetime object rather than trying to attempt to alter it using a regular expression. This can then be converted back into the required date format more easily. With regards to leading zeros though, the formatting options … Read more
Define your function example as this:- def exemple(func_name): def dostuff1(): print(‘Stuff 1’) def dostuff2(): print(‘Stuff 2’) def dostuff3(): print(‘Stuff 3’) func_dic = { “dostuff1” : dostuff1, “dostuff2” : dostuff2, “dostuff3” : dostuff3 } return func_dic[func_name] Then call your function in the other function like this: def training(): exemple(“dostuff2”)() I hope it helps! 3 solved Python … Read more
I wonder how you are able to run this program, seems to be some harry potter stuff. For me its typo in this line “ele” == input(“”) and gives Syntax error . So just fix this with ele = input() and replace “ele” with ele in all if/elif checks i.e if ele == “H”:it will … Read more
If the rest of the code is correct, this should do: def add_sighting(session, spawn_id, pokemon): obj = Sighting( pokemon_id=pokemon[‘id’], spawn_id=spawn_id, expire_timestamp=pokemon[‘disappear_time’], normalized_timestamp=normalize_timestamp(pokemon[‘disappear_time’]), lat=pokemon[‘lat’], lon=pokemon[‘lng’], ) # Check if there isn’t the same entry already existing = session.query(Sighting) \ .filter(Sighting.pokemon_id == obj.pokemon_id) \ .filter(Sighting.spawn_id == obj.spawn_id) \ .filter(Sighting.expire_timestamp > obj.expire_timestamp – 10) \ .filter(Sighting.expire_timestamp < obj.expire_timestamp … Read more
time.strptime(“2/8/2015 22:22”, “%d/%m/%Y %H:%M”) 3 solved How to parse dates to get the year in Python [duplicate]
Keeping to your original idea, you were fairly close. Note, Python already keeps a handy list of lower case letters: import string alphabet = string.ascii_lowercase message = input(‘Please insert the message you want to encrypt: ‘) key = int(input(‘What key value do you want in your encryption? ‘)) output = [] for m in message: … Read more
Use True/False instead of true/false. You can consider True and False as somehow ‘keywords’ in Python. For Python scripts, you don’t use def main():. Instead, try using if __name__ == ‘__main__’: under global scope. Look at this for more info. You have to print something out rather than just return a boolean variable, by using … Read more
Writing a function to print letters of a string according to their frequency compalsarily using dictionary and tuple [closed] solved Writing a function to print letters of a string according to their frequency compalsarily using dictionary and tuple [closed]
amount = int(input(“Enter the amount of numbers that you have: “)) numbers = [] for i in range(amount): new = input(‘Enter number {}: ‘.format(i+1)) numbers.append(new) print(numbers) You should probably do some reading on loops in Python. 2 solved Python take a variable number of inputs? [closed]
Luckily my crystal ball is working today so I can guess what you mean when you say it isn’t working. Of course, you might have made it easier by actually explaining, but there we go. If you just want a list of (x, y) pairs then zip is the way to go. The syntax you … Read more