[ad_1] no (at least not automagically … ) Install python … install packages … make venv’s using –include_site_packages (pycharm makes this quite easy with their GUI create new venv thing) I think you must have some globally installed python that you can create venvs from pip is the python package manager, this is how you … Read more
[ad_1] Based on @Kevin s suggestion with “ast.parse“ I could use def hasRecursion(tree): for node in [n for n in ast.walk(tree)]: nodecls = node.__class__ nodename = nodecls.__name__ if isinstance(node, (ast.For, ast.While)): for nodeChild in node.body: #node.body Or ast.iter_child_nodes(node) if isinstance(nodeChild, (ast.For, ast.While)): return True return False expr=””” for i in 3: print(“first loop”) for j … Read more
[ad_1] You may try using the regex pattern l.*t.*e, e.g. my_str = “little” if re.match(r’l.*t.*e’, my_str): print “MATCH” More generally, if you want to find l..t..e within a single word, then try: my_str = “little” if re.match(r’\b\w*l.*t.*e\w*\b’, my_str): print “MATCH” 2 [ad_2] solved regex, search a few letter in one word [closed]
[ad_1] you can use basic for loop and if statement to check values: List_1 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, 5), 5, 6, 7)] List_2 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4.4, 5), 5, 6, 7)] List_1 = list(List_1[0]) # [(1.1, 2, 3), (1.1, 2, 3, 4), (3, … Read more
[ad_1] Assuming your data object is a simple dict or list,all you need to do is: with open(output_path, ‘w’) as f: json.dump(data, f, sort_keys=True, indent=4) This will correctly dump to the output file. 3 [ad_2] solved How to fix ‘\n’ from json?
[ad_1] You shouldn’t try to manipulate them as strings – this will be fragile and very specific to the strings. Instead, parse the strings into dictionaries, do whatever manipulations you want, and then dump them back to JSON strings: import json s1 = ‘{“step”:”example step”, “data”:”example data”, “result”:”example result”}’ s2 = ‘{“attachments”:[ { “data”:”gsddfgdsfg…(base64) “, … Read more
[ad_1] Welcome to StackOverflow! It appears your variable: mf_json_data defined at: https://github.com/apalmesano2/assignment2_part2/blob/master/portfolio/models.py#L113 is failing to return a value, resulting in mf_request = None. I recommend you ensure your mf_json_data = requests.get(mf_url).json() is pulling appropriately. Try debugging with something like this: mf_request = requests.get(mf_url) print(‘MF Request:’, mf_request, ‘MF Request Type: ‘, type(mf_request)) if mf_request.status_code != 200: … Read more
[ad_1] It seems you are new to the world of programming. “sys.argv” is used to take Command Line Arguments. when you run as “python sample.py”, the variable sys.argv will be a single element list i.e. [“sample.py”] len(sys.argv) is 1 in this case The Expected Working of the program is: when you run as “python sample.py … Read more
[ad_1] If you don’t want to refresh the page manually, you can add the following meta tag to your tag that will refresh it automatically. <meta http-equiv=”refresh” content=”5″> The above meta tag will refresh the page every 5 seconds. 3 [ad_2] solved Updating asp.net JPG File
[ad_1] you can also use split() function to do your task str=”published = 6/11/2019 at 8:02 AM” str=str.split(‘=’) str=str[1].split(‘at’) print(‘published date=”,str[0],”\npublished time=”,str[1]) you will get the same result 2 [ad_2] solved xpath issue in extracting data [duplicate]
[ad_1] The output that you seem to want can be obtained with : [{“projectname” : key} for key in list1] 1 [ad_2] solved convert the python list to the dictionary with the same key but with different values
[ad_1] OP: i have written code but it hangs after giving input.. after ctr+c it shows last call on if statement. Because: Imagine you’ve entered an incorrrect number, the condition fails, the loop continues, it checks the same condition and fails again, keeps going on and on. What you need: Put the ug = int(input(“Guess … Read more
[ad_1] It is because the if statement is not indented properly and its condition is not specified as a string ‘help’: while 1: userCommand = input(‘Type a command (type \’help\’ for syntax): ‘) if userCommand == ‘help’: print (‘flight: this command will be used to list a flight’) break [ad_2] solved How do I add … Read more
[ad_1] Use the json package and load the json. Assuming it is a string in memory (as opposed to a .json file): jsonstring = “”” [ { “issuer_ca_id”: 16418, “issuer_name”: “C=US, O=Let’s Encrypt, CN=Let’s Encrypt Authority X3”, “name_value”: “sub.test.com”, “min_cert_id”: 325717795, “min_entry_timestamp”: “2018-02-08T16:47:39.089”, “not_before”: “2018-02-08T15:47:39” }, { “issuer_ca_id”:9324, “issuer_name”:”C=US, O=Amazon, OU=Server CA 1B, CN=Amazon”, “name_value”:”marketplace.test.com”, … Read more
[ad_1] As I understand, the number of groups in a regex pattern is pre-determined. If you need to iterate over all the matches, you could do something like this: import re text = “””some value {arg1} {arg2} {arg3} another value {arg1} idkhere {arg1} {arg2}””” pattern = re.compile(r”{arg\d}”) for i in re.findall(pattern, text): print(i) 2 [ad_2] … Read more