This is one of the easiest problem ever. This is my solution (since you tagged your post for Python 3): name = input(‘Enter your name: ‘) print(“Welcome”, name) For Python 2, just change input to raw_input, and remove the parenthesis of the print function. 1 solved Ask the user for its name using raw_input [closed]
argv stands for argument value and it represents the arguments passed to your program when it is launched from the command line. For example, if your program is called example.py, and you run it like this: $ example.py ‘hello’ Then argv is hello. raw_input is a way to prompt the user for some input. Basically, … Read more
For start i suggest for you to start with Tkinter library (built in library). This is a simple program using Tkinter gui. import Tkinter class simpleapp_tk(Tkinter.Tk): def __init__(self,parent): Tkinter.Tk.__init__(self,parent) self.parent = parent self.initialize() def initialize(self): self.grid() self.entryVariable = Tkinter.StringVar() self.entry = Tkinter.Entry(self,textvariable=self.entryVariable) self.entry.grid(column=0,row=0,sticky=’EW’) self.entry.bind(“<Return>”, self.OnPressEnter) self.entryVariable.set(u”Enter text here.”) button = Tkinter.Button(self,text=u”Click me !”, command=self.OnButtonClick) button.grid(column=1,row=0) … Read more
It is because the if statement is not indented properly and its condition is not specified as a string ‘help’: while 1: userCommand = input(‘Type a command (type \’help\’ for syntax): ‘) if userCommand == ‘help’: print (‘flight: this command will be used to list a flight’) break solved How do I add ‘if’ commands … Read more
raw_input() takes in a line of input as a string. The .split() string method produces a list of the whitespace-separated words in a string. int() parses a string as an int. So putting that together, you can read the input you want using t = int(raw_input()) cases = [] for i in range(t): cases.append( map(int, … Read more