The comments actually helped me get the answer by pointing me to openpyxl. I’m posting it here if anyone else had it. import openpyxl wb = openpyxl.load_workbook(‘Roster Report.xlsx’) header_text = str(wb.active.HeaderFooter) wb.close() I didn’t see a way in xlrd to read the header, only to write it. 2 solved Read Excel Text Header Using Python
You coded your program a bit awkwardly. However, that aside, you can get your method to output by using the print statement as opposed to the return. Otherwise, when you return something from a function you need to assign what is returned to some variable(s). For example: def getter(): return “Hello, world” r = getter() … Read more
I have come with the solution, Thanks for the every on who support me and encourage me. S = [‘abcd5934′,’abcd5935′,’abcd5936′,’abcd7154′,’abcd7155′,’abcd7156′] Yesterday = [(u’abcd7154′, u’1′), (u’abcd7155′, u’2′), (u’abcd7156′, u’3’)] Today = [] y_servers = [srvr[0] for srvr in Yesterday] value = [Yes[1] for Yes in Yesterday] print y_servers print value v = 0 for srv in … Read more
One problem with your code is that the index n1 by definition does not exist in your list. Python lists indices start at 0, so a list with length 3 only has indices 0-2. mylist = [“a”, “b”, “c”] print(len(mylist)) # 3 print(mylist[3]) # IndexError! print(mylist[2]) # “c” Instead of this: n1 = len(p1) Try … Read more
You can read all data at a moment: with open(input_file, ‘r’, encoding=’utf-8′) as f: data = f.read() You can read all data line-by-line: with open(input_file, ‘r’, encoding=’utf-8′) as f: for line in f.readlines(): # todo smth solved Input from a file [closed]
I think need: df[‘Id’] = [‘Author-Id-{:03d}’.format(x) for x in range(1, 151)] 0 solved add column in dataframe
For nicely distributed data, I expect that the most effective way will be to start with a k-means clustering. If each resulting cluster fits within the schools’ capacities, you have a solution. However, your “worry” case is where at least one school is over capacity. For instance, you have 20 children on the north side … Read more
Use split() numbers = input(“Please type a code: “).split() # [’16’, ’25’, ’20’, ‘8’, ’14’, ‘0’, ‘9’, ‘,19’, ‘0’, ‘3’, ’15’, ’15’, ’12’] Use for .. in .. for num in numbers: print( x[int(num)] ) If you use 0 as space you have to add space at the begginig of list x = [‘ ‘, … Read more
I think you are looking for something along the lines of this: # run with python dynamictopo.py z n # e.g.: python dynamictopo.py 3 2 import sys z = int(sys.argv[1]) # number of nodes n = int(sys.argv[2]) # number of hosts nodes = [] for i in range(0, z): nodes.append(“s” + str(i + 1)) print(nodes) … Read more
You can solve it using regex. Like this e.g. import re expected_output = re.findall(‘(?:{0})\s+?([^\s]+)’.format(‘|’.join(key_words)), text_string) Explanation (?:{0}) Is getting your key_words list and creating a non-capturing group with all the words inside this list. \s+? Add a lazy quantifier so it will get all spaces after any of the former occurrences up to the next … Read more
It is going to depend on the type of data in the list. input returns everything as str. So if the list data type is float then the if statement will evaluate as True. For int data use the following: items = [variable1, variable2, variable3] choice = input(“Input variable here: “) if int(choice) not in … Read more
Alright, so first of all we need to improve the program layout , maybe call in some functions would be useful. Here is some tips to fix the program. First of all use : if username.strip() and password.strip() in line: [Use the .strip() function so it will match a word. Your program is inefficient because … Read more
You need to put one “)” the line before the if and also the last “else” is missing a “:” solved Python3: Error with colon in if statement
There is no easy way to do it. Best option will be to write a program that extracts the information from the tags and then puts it into a pandas dataframe which you can export as csv. solved Add multiple xml files together in command line
The code below did what I needed. with open(“finalfile.txt”, ‘w’, encoding=’utf-8′) as File2, open(“test.txt”, “r”, encoding=’utf-8′) as File1: previous_line = “” new_line = “” double_dash_prev_line = False single_dash_prev_line = False for line in File1: current_line = line if line[0] == “-“: if line[1] != “-“: if single_dash_prev_line == False and double_dash_prev_line == False: new_line = … Read more