[Solved] Getting a Parse error: syntax error, unexpected ‘;’ [closed]
Your quotation marks around the command string are wrong. 3 solved Getting a Parse error: syntax error, unexpected ‘;’ [closed]
Your quotation marks around the command string are wrong. 3 solved Getting a Parse error: syntax error, unexpected ‘;’ [closed]
HTML Parser is a HTML parser for Java. http://htmlparser.sourceforge.net/ 1 solved Html parser with java [closed]
A simpler expression should do the trick: var str = “https://web.archive.org/web/20030328195612/https://www.iskme.org:80/”; var url = str.match(/.*(https?:.*)/)[1]; The first .* will consume as many characters as possible up until the last occurrence of http(s): in the search string. 4 solved Javascript regex: issue when trying to parse both http and https instances of a natively archived string … Read more
Wooble is correct, you are missing a closing bracket on one of your if statements. The following code should do the trick <?php //Funcao que vai abrir o arquivo php que faz conexao com o servidor require_once (“sistemadelogin.php”); $descricao = $_POST[descimagem]; $nomeFOTOG = $_FILES[‘fotoimagem’][‘name’]; $nomeFOTOP = $_FILES[‘miniImagem’][‘name’]; $tmpFOTOG = $_FILES[‘fotoimagem’][‘tmp_name’]; $tmpFOTOP = $_FILES[‘miniImagem’][‘tmp_name’]; $destinoG = … Read more
You could use Scheme, it’s a nice Lisp-like language that has built-in support for complex numbers. Also, since in Scheme data is code, it is really easy to turn user input into executable code. Chicken Scheme is a popular variant. Other popular languages with built-in complex number support are: R: use i as suffix for … Read more
use the following custom method -(NSArray *)stringArrayFromJsonFile:(NSString *)jsonFileName withKey:(NSString *)key { NSData *fileContents = [NSData dataWithContentsOfFile:[[NSBundle mainBundle] pathForResource:jsonFileName ofType:@”json”]]; NSError *error; NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:fileContents options:kNilOptions error:&error]; NSArray * stringArray = [dict objectForKey:key]; return stringArray; } now call that method like NSArray* stringArray = [self stringArrayFromJsonFile:@”yourJsonFileName” withKey:@”categories”]; 1 solved How to Parse an Array … Read more
Better to use an array. eval() is the function for “double parsing” (but could be really dangerous !) solved How to “parse” js twice? [closed]
This expression (GUInumber1 >= 0 || <= 0) is not correct. You will need something on both sides of the <= operator. solved Strings in ternary operators interacting with numbers [closed]
Try this: string s = “10.11.2017. 0:00:00”; DateTime expireDate = DateTime.ParseExact(s, “dd.MM.yyyy. H:mm:ss”, CultureInfo.InvariantCulture); 2 solved String was not recognized as a valid DateTime even if I provide valid Date format [closed]
Basically ‘[]’ this represent as JSONArray and ‘{}’ this represent JSONObject try { JSONArray jsonArray = new JSONArray(response); for(int i=0; i<jsonArray.length(); i++){ JSONObject jsonObject = jsonArray.getJSONObject(i); String id = jsonObject.getString(“id”); String name = jsonObject.getString(“name”); String surname = jsonObject.getString(“surname”); String il = jsonObject.getString(“il”); } } catch (JSONException e) { e.printStackTrace(); } 2 solved How to parse … Read more
split your string on space to get Logging and v0.12.4 remove (substring) v from v0.12.4 split 0.12.4 on dot (use split(“\\.”) since dot is special in regex) you can also parse each “0” “12” “4” to integer (Integer.parseInt can be helpful). 4 solved Parsing String and Int in java
If it’s always going to be “NDC: [number]”, you can use a fairly simple Regular Expression. var re = new System.Text.RegularExpressions.Regex(@”NDC\:\s(\d{11})”); var phrase = “Rx: RX15046522B Brand: LEVOTHYROXINE SODIUM Generic: LEVOTHYROXINE SODIUM NDC: 00378180001 Barcode: 0378180001 Strength: 25 mcg Form: Tablet Color: orange Marking: Shape: oblong”; if (re.IsMatch(phrase)) { var match = re.Match(phrase); // entire … Read more
Use Regex. I added a ‘\n’ to and of each line to look like code was read from a file. You can use StreamReader instead of StringReader to read from a file. See code below : using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.IO; using System.Text.RegularExpressions; namespace ConsoleApplication51 { class Program { static … Read more
File formats are specification of structure of a file. They’re usually in binary but in your case and in many other cases, they’re text. The first thing you need to do is decide on the structure of your document and then read it like by line. You can also use tools that make this process … Read more
if you have the line already, it’s easiest to use sscanf() to do this: long a, b; if(sscanf(line, “%ld,%ld”, &a, &b) == 2) { /* Successfully parsed two long integers, now store them somewhere I guess. */ } Note that it’s a good idea to check the return value of sscanf(), this protects you from … Read more