You are multiplying a list by a float. You should multiply each row of the matrix with words. Something like this will work. multiply_nonspam_test = [] for row in transpose_test_feature: multiply_nonspam_test.append([x*y for x,y in zip(row, log_train_probs_nonspam_words)]) print multiply_nonspam_test 0 solved can’t multiply matrix and list which type ‘float’
That is double’s precision. You could use cookies = Math.round( cookies * 100.0 ) / 100.0; solved Java doesn’t know how to multiply? What? [duplicate]
You could do something like this: string = ” for t in range(1,8): if t % 2 == 0: # if t is even multiply t by 3 and add t to the string string += str(t * 3) + ‘ ‘ else: # if t is odd simply add t to the string string … Read more
$con = mysqli_connect(“localhost”, “root”, “”, “zoo”); if (mysqli_connect_error()) { echo “Failed to connect” . mysqli_connect_error(); } $sel = “select (quantity* bill) as total from animal inner join price on animal.id=price.animal_id group by price.animal_id”; $result = mysqli_query($con, $sel); while ($row = mysqli_fetch_array($result)) { echo “<tr>”; echo”<td>” . $row[‘total’] . “</td>”; } Before copy and paste check … Read more
Sqlite uses ., not , for the decimal point in a floating pointer number (Do any sql databases accept a comma for it?). When you multiply a number (4) by a string (‘99,99′) the leading numeric portion of the string is converted to a number, so you’re seeing the result of 4 * 99. (SELECT … Read more
With the full code in the question we can now see it’s an integer overflow. 10000 * 180 * 3600 = 6,480,000,000. This is greater than 2,147,483,648 which is the max value of a 32-bit signed int. The results of the multiplication overflows to -2,109,934,592 and is then converted to double. To get the right … Read more
Your code is duplicating every corresponding list (values) in example1 as many times as the values in example2. Your code is similar to: >>>>two_items = [“A”,”B”] >>>>number = [3] >>>>result = two_items*number[0] [‘A’, ‘B’, ‘A’, ‘B’, ‘A’, ‘B’] To make this clear, it works like string multiplication: >>>>my_string=”Hello ” >>>>print(my_string * number[0]) Hello Hello Hello … Read more
I’m guessing that tsidx and StreamDataBlockSize are Integer types. The largest number an Integer type can hold is 2,147,483,647. The multiplication in brackets is then done expecting an integer result, but the answer is out of the range of Integer types. Change your code to .. Dim position As Long = hisFileHeader.StreamStartDataPosition + (CLng(TSIdx) * … Read more
For the simplest solution, use apply for this: (define (multiply-all lst) (apply * lst)) If you need to build the procedure from scratch, just remember that the base case (an empty list) should return 1, and the recursive step should multiply the current value using the standard solution template, like this: (define (multiply-all lst) (if … Read more