[ad_1] Any number can be represented as a difference of squares if it is odd, or a multiple of 4. The problem arises when a product has only a single 2 in the prime factorisation. So we can mark them. (i.e all the 2) Given this we can easily deduce that only what is not … Read more
[ad_1] import random n = int(input(‘Введите кол-во столбцов матрицы: ‘)) #columns m = int(input(‘Введите кол-во строк матрицы: ‘)) #rows matrix = [[random.randrange(0, 10) for y in range(n)] for x in range(m)] for i in range(m): for j in range(n): print(matrix[i][j], end = ” “) print() max_x = 0 for i in range(m): for j in … Read more
[ad_1] Divide number by 6 and round to the nearest number. Your first 5 numbers were calculated in step 1. Last number = Initial number – (5 x number from step 1) 0 [ad_2] solved Split an uneven number in even shares
[ad_1] 121 = 11 * 11 would be the first non-prime listed as prime by your code. So your code is only a solution up to n = 120. I.e.: No. 3 [ad_2] solved Is this a good approach for finding number of prime numbers within a certain range? [closed]
[ad_1] You can predict your output by following each step manually. In your case, each func call would work like the following chart: func(5) + +–+ func(4) | + | +–+ func(3) | | + | | +–+ func(2) | | | + | | | +–+ func(1) = 3 | | | | | … Read more
[ad_1] What you shared is not valid python code. Here is an example of code that will accomplish what you are asking: # define function: def CalculateMortgage(p, i, n): # calculate numerator: numerator = p * (i *(1+i) ** n) # calculate denominator: denominator = ((1+i) ** n – 1) # calculate mortgage: mortgage = … Read more
[ad_1] To graduate – You’ll need it for sure. An easy example are integrals, derivatives and stuff like that. A lot of subjects, at least in my university requires a basic understanding of maths. Another thing is what kind of a programmer you wanna be. Sure I guess you do not always have to use … Read more
[ad_1] $answer = 1; for($x=1;$x<6;$x++){ $answer+=5*$x; } echo $answer; 3 [ad_2] solved How I use for loop to get the addition result? [closed]
[ad_1] Not sure if I get your question correctly… First, if what you want is to show a progressbar with some value that’s not 100… why not simply set the progres bar’s Maximum to your value (156761 in your example) and set Value to whatever progress it has? Now, if the progress bar for whatever … Read more
[ad_1] Position of the first circle is described as x1 = x1_0 + vx1 * t y1 = y1_0 + vy1 * t where x10 is initial x-coordinate, vx1 is x-component of velocity vector, t is time. Make similar expression for the second circle center, build expression for squared distance and find time when squared … Read more
Introduction [ad_1] Maths can be a tricky subject for many people, but understanding how to calculate two percentage increases can be a useful skill to have. In this article, we will discuss how to calculate two percentage increases and provide some examples to help you understand the concept. We will also provide some tips and … Read more
[ad_1] First: You did not use D: I suppose instead of B / 6, it should read B x D, where D can be either 20% or 16,666…% There is a mistake: B x C is not 3.60 for the given values (B=20, C=15%), it is 3. This is a matter of mathematical deduction: Given … Read more
[ad_1] While this is a too basic question, here’s a possible solution. You only have to check the second variable, the first one is okay even if it’s 0: <?php $result = mysql_query(“SELECT * FROM high ORDER BY Runecraftlvl DESC LIMIT 20”); while($row = mysql_fetch_array($result)) { echo ($row[‘deaths’] != 0) ? $row[‘kills’] / $row[‘deaths’] : … Read more
[ad_1] From the modulo laws on DAle’s linked Wikipedia page (on your previous question), we can obtain two formulas: From the first formula it is clear that we can iteratively calculate the modulo for n from the result for n / 2. This is done by the lines x = x * x; x = … Read more
[ad_1] According to your list the Color rotates in a 10 years cycle and then has always 2 subsequent years with same color. Given that rule you can calculate an index in a field of year colors. #include <vector> #include <string> #include <iostream> using namespace std; int main() { const int base_year = 1984; vector<string> … Read more