The modulo operator, more or less, just gives you the remainder of the division. So: 12 % 4 = 0 since 12 / 4 = 3 remainder 0 Whereas, since 12 doesn’t divide 4: 4 % 12 = 4 since 4 / 12 = 0 remainder 4 For more information, see the Wikipedia article, or … Read more
I think it’s a very bad idea to calculate two very large numbers and hope that the quotient comes out as something sensible. Start by taking the natural log: ln(n!/(q!)^r) = ln(n!) – r*ln(q!) You can use gammaln() for the two function values, simplify, then take exp() to get the result you want: value = … Read more
your code problem is int i = 0 start with 0 and next line if (N%i==0) so 10/0 is not possible throw a error something like java.lang.ArithmeticException: / by zero is not possible and you loop through result.length, you need to loop through i your parent loop and put condition inside if (N%i==0) and you … Read more
There are many possible solutions to this problem. Here’s a reusable solution that simply decrements from 4 to 1 and adds the expected number of 1’s and 0’s. Loops used : 1 def sequence(n): string = “” for i in range(n): string+=’1’*(n-i) string+=’0’*(n-i) return string print sequence(4) There’s another single-line elegant and more pythonic way … Read more
The problem can be expressed as finding the 3-by-3 matrix M such that the coordinates of a point P can be converted between the old coordinate system (P_old, 3 rows) and the new coordinate system (P_new, 3 rows). This is an affine transformation: P_old = Center + M * P_new (1) The (matrix-vector) multiplication with … Read more
Actually the code in question works on unix systems, but usually the problem is that calls like fmt.Scanf(“%f”, &x1) does not consume newlines, but quoting from package doc of fmt: Scanning: Scan, Fscan, Sscan treat newlines in the input as spaces. And on Windows the newline is not a single \n character but \r\n, so … Read more
You must create a different random number for each thread (more details) so try this code in your main method: for (int i = 0; i < 10; i++) { int temp = i; threadArray[i] = new Thread(() => simThread(temp)); Console.WriteLine(“[He Thong] PID ” + i.ToString() + ” duoc khoi tao”); threadArray[i].Start(); Thread.Sleep(20); } and … Read more
Your question is very unclear; in the future, you’ll probably get better results if you post a clear question with a code sample that actually compiles and demonstrates the problem you’re actually having. Don’t make people guess what the problem is. If what you want to do is display a double-precision floating point number without … Read more
If you have the distance in miles, all you have to know is the conversion from miles to feet: 1 mile == 5,280 feet Are the calculations you posted incorrect in some way? http://www.google.com/search?gcx=c&sourceid=chrome&ie=UTF-8&q=convert+miles+to+feet solved How can calculate distance in feet between two places? [closed]
Create a function that gets a product weight and returns a bag number – the one which has the least free space that’s still enough to fit. Put it in the bag. Repeat until done. $bags = array(60,80,20,10,80,100,90); $containers = array(1=>100,2=>100,3=>100,4=>100); // number -> free space $placement = array(); rsort($bags); // biggest first – usually … Read more
Math.round() will return the nearest integer value as described here For your input Math.round(1.53*20)/20 it will first calculate 1.53*20 answer is 30.6 Then your expression becomes Math.round(30.6)/20 After that result of Math.round(30.6) is 31 (nearest integer) Then your statement becomes 31/20 which is 1.55 solved Why does Math.round(1.53*20)/20 = 1.55? How does this actually work?
Binary floating point math is like this. In most programming languages, it is based on the IEEE 754 standard. The crux of the problem is that numbers are represented in this format as a whole number times a power of two; rational numbers (such as 0.1, which is 1/10) whose denominator is not a power … Read more