Neither. Using a loop has less overhead than LINQ, so that is a good start. Use the < operator in the loop condition, that is the standard way of writing such a loop, so it’s more likely that the compiler will recognise it and optimise it properly. Using Math.Pow to square a number is not … Read more
Instead of the standard for loop to go through an array, for example: for($i = 0; $i < count($array); $i++) { echo $array[$i] . ” “; } Outputs “one two three four five”. Just set $i equal to 1 instead, like so: for($i = 1; $i < count($array); $i++) { echo $array[$i] . ” “; … Read more
You have two nested loops that each execute anyLines.length times. If there are four lines in the file, the inner loop will execute 16 times. 2 solved Why is this code looping 16 times? [duplicate]
You are confusing pointers with arrays. A pointer just points; declaring a pointer does not reserve memory, it just creates a pointer variable pointing to some undefined place. Corrected program: char *recepcao(char *receber) { scanf(“%s”, receber); return receber; } int conversao(char *string) { int i, j; for(i=0; string[i]!=’\0′; ++i) { continue; } int var[100]; int … Read more
If I understand you correctly, you want to loop while a condition is true and exit the loop when the condition become false. So you should be using the while control-flow operator, not for. i <- 1 while(i<=length(blocks) & length(blocks[[i]])!=0){ i <- i+1 } # check that we exited the loop because there was a … Read more
print value (prints 1) ++ (adds 1 to $value) check if value is > or = to 10 and break if it is that is why you loop never gets to printing 10 since it breaks when the value is equal to 10 solved it may seem like a silly question but it’s confusing to … Read more
First of all a few things to help you with your code: Try following atleast a few conventions (tab your code in for example) In your if statements and foor loops you are handeling way too many thing. If the first statement didn’t catch that the value is under 60, there is no need to … Read more
If just want to handle “quit” or a float, that’s easy: total = 0.0 while True: value = raw_input(“enter a number or quit to finish”)) if value == “quit”: break total += float(value) print total But if the user types, say, qiut or 2..137, the program will bail out with a ValueError. How do you … Read more
It will enter the for loop first when i = 0. Immediately after it will enter the while loop and continue running indefinitely as i will always be 0 and therefore < 3. You perhaps need to deal with j in the break condition of inner loop for avoiding an infinite loop. solved How does … Read more
Only the second inner loop needs to be adjusted a little bit (changes in bold): for (int k = i; k >= 1; k–) { System.out.printf(” %2d”, k * k); } The first inner loop for indention runs n-i times, so the second inner loop have to do the rest: i..1. And you have to … Read more
I was able to figure out something a little bit less messy by using an array, probably still not the best way of doing it but it’s the best that I could come up with. length_of_charts = int(input(“Enter how many songs you have in each of your weekly charts: “)) lengths = [3, 5, 10, … Read more
Let’s step it through: f(12, 18) -> a = 12, b = 18 int a1 = a, b1 = b; -> a1 = 12, b1 = 18 while (a1 != b1) -> not equal -> do the loop if (a1 < b1) a1 += a; -> a1 = 24 while (a1 != b1) -> not … Read more
#!/bin/bash for ((;;)); do for i in {1..10}; do ./${i}.sh done done 0 solved Linux run scripts one after other in loop [closed]
Just use a regular for loop to iterate over all arrays at once: String[] item ={“[1]hotdog”, “[2]eggpie”,”[3]menudo”,”[4]pizza”,”[5]lumpia”}; int[] cost = {5, 10, 15, 20, 25}; int[] selling = {10,15,20,25,30,}; int[] qty = {2,4,6,8,10}; for (int i = 0; i < item.length; i++) { System.out.println(” ” +item[i]+”\t”+cost[i]+”\t\t”+selling[i]+”\t\t”+qty[i]); } I would recommend putting all of these fields … Read more
in your image is in quotes, is an f-string, but they forgot to add the f year = [2016,2017,2018,2019,2020] for i in year: rtx_price = (data.loc[f'{year}-07-31′, ‘RTX’]) 6 solved Python for loops with an array [closed]