range range(stop) range(start, stop[, step]) >>> for n in range(17, 100, 10): print n 17 27 37 47 57 67 77 87 97 solved Writing a loop with a step size 10, to print out all 2-digit numbers ending in 7 in increasing order in python
I tried to run that and my outputs for r1 and r2 are qwdaweqwe asdas–sd (two spaces) and basically it is what the code should be doing. But if I get your intention right, you want to work with those empty strings. Then you should be feeding your function with different numbers, because array indexing … Read more
First I’m going to remove all of the I/O (except for outputting the result), get rid of the decryption piece for brevity, and write encrypt(String) and encrypt(char) as pure functions. public class EncryptionMain { public static void main(String args[]){ System.out.println(encrypt(“Hello”)); } static String encrypt(String plaintext) { StringBuilder ciphertext = new StringBuilder(plaintext); for (int i = … Read more
Never wonder; use Google Caliper to find out. Since there has been quite a bit of discussion around the relative weights of testing against zero vs. upper limit and incrementing vs. decrementing, here’s the Cartesian product of all these cases: import java.util.Random; import com.google.caliper.Runner; import com.google.caliper.SimpleBenchmark; public class Performance extends SimpleBenchmark { static final Random … Read more
this is shorthand pseudo code because you have to code this yourself: min = max = total = user_input count = 0 do { count++ input = get_input total += input min or max maybe = input } while (input !=100) average = total / count print stuff good luck 1 solved How to count … Read more
It’s a for-each loop. Num is some object which implements Iterable<String> like a String[] array or a collection like for example ArrayList<String>. The loop is executed once for each entry in that data structure. In each iteration of the loop, String Number is a different entry. What the loop does exactly, is to read each … Read more
Just about every angle-bracket language I know follows the following conventions: The condition of an if statement normally goes in parenthesis You shouldn’t have a curly brace at the end of turnCard(‘hit5′}; You shouldn’t have a ; at the end of your if-statements(or your for statement) Some languages allow you to use single-quotes like that … Read more
If I was coding this myself (rather than trying to explain a method for someone else to code this) I would do the following: Type ValueAndLevel dataValue As String dataLevel As Long End Type Dim myData() As ValueAndLevel Sub Export1() ReDim myData(1 To 1) ‘Start the process in column 1, with level being 0 Process … Read more
function myFunction(num) { let i = 0; let str = “”; while(i < num) { i++; str = str + i + “,”; if(i % 3 === 0) { i = 3 + i; } } str = str.substring(0, str.length – 1); console.log(str); } myFunction( 29 ); 2 solved How do I write a loop … Read more
List<Type> list = … list.removeIf(item -> item.getId() == something); As the name suggests, removeIf() removes all elements if they satisfy the predicate. 7 solved How to remove some items from an arraylist without loop and less time complexity?
You can use the while loop as follows: int i=1; while(i<=7) { sal = load(); rate = calcRate(sal); calcRaise(sal, rate, &raise, &totraise); calcNewSal(sal, raise, &newsal, &totnewsal); calcTotSal(&sal, &totsal); print(sal, rate, raise, newsal, totsal, totraise, totnewsal); fflush(stdin); i++; } And the do-while as follows: int i=1; do { sal = load(); rate = calcRate(sal); calcRaise(sal, rate, … Read more
its easy to get confused when you have a big chunk of code like this … instead try and split your problem into smaller parts start with a function to get the details of only one student def get_student_detail(num_tests): # get the detail for just 1 student! student_name = input(“Enter Student Name:”) scores = [] … Read more
The int and unsigned int variables take exactly the same amount of memory and represented in the resulting assembly code in exactly the same way. Thus adding unsigned here changes nothing from the performance point of view. In general you should not worry. The loop counter is definitely not the biggest memory consuming thing in … Read more
You could write tokenize which consumes your text input and produces a stream of tokens – const input = [ ‘7’, ‘3’, ‘+’, ‘6’, ‘x’, ‘8’, ‘+’, ‘5’, ‘4’, ‘x’, ‘2’ ] function* tokenize (es) { let r = 0, n for (const e of es) { switch (e) { case “+”: case “x”: yield … Read more
First of all, that’s a weird way to put goto to use. You don’t need a goto at all and can just use a simple loop instead. for(int i = 0; i < 10; i++) { if(i == 5) { printf(“Hello World “); } printf(“%i “, i + 1); } or if you really want … Read more