Don’t use getClass().toString() to compare types. Use instanceof and try to group types by common interfaces when possible. For example CharSequence is a common interface for String, StringBuilder, and StringBuffer. Here is one way. You may want to rework the compare method to compare whatever types you have such as Date or URL or custom … Read more
declaring a new empty array var lstObject = []; access the array var o = listObject[0]; These are the basics of JS. Please read about JavaScript Arrays solved convert Java to javascript code [closed]
Almost all that this code do is organizing input and output except only this line: count=Collections.frequency(list,x); This is the only line where real computations happen. Actually, it’s time and space complexity is determined by the standard java.util.Collections.frequency method which should have pretty good time and space characteristics for such a trivial case. 1 solved How … Read more
Use this: public void someMethod(int[] arr){ for(int i=arr.length-1; i >= 0; i–){ if(arr[i] <= 8){ arr[i]+=1; }else if(arr[i] ==9){ arr[i] = 0; } } } Refer https://docs.oracle.com/javase/tutorial/java/nutsandbolts/for.html for better undersatnding of for loop construct. solved (Java) Go thru array beginning at the last index [closed]
Mixing types is not a java concept however you can compare, which is what you are looking for. Since newvalid is an array lets loop it and see if valid is inside. boolean contains = false; for (char c : newvalid) { if (c == valid) { contains = true; break; } } if (contains) … Read more
Assuming your PHP script is producing correct JSON. Try changing this part JSONArray jArray = new JSONArray(result); to this. JSONObject jObject = new JSONObject(result); JSONArray jArray = jObject.getJSONArray(“NomTableau”); 2 solved org.json.JSONException: Value Exception of type java.lang.String cannot be converted to JSONArray
Without context, it’s just hard to understand your question. The last 3 bytes of the hash “742da831d2b657fa53d347301ec610e1ebf8a3d0” you give are “f8a3d0”, which are the last 6 characters “F8A3D0” in “SpeedTouchF8A3D0”. The first 5 bytes of the hash “742da831d2b657fa53d347301ec610e1ebf8a3d0” are “742da831d2”, which gives the 10-character string you are referring to: “742DA831D2”. 1 solved How many bytes … Read more
Either make the information available by using statics (not recommended), use some kind of database (could be as simple as a text file) or pass an Intent along with your Activity. A nice tutorial on adding information to an Intent is found here: http://startandroid.ru/en/lessons/complete-list/241-lesson-28-extras-passing-data-using-intent.html 0 solved How to access a HashMap from another class
Maybe your method should look like this : public boolean checkSuper(int num) { int n1; int n2 = num; while(num > 0) { if(num % 10 == 0) { return false; } n1 = num % 10; if(n2 % n1 == 0) { num = num / 10; } else { return false; } } … Read more
You have to escape the \ in Java, so replace all your \ with \ (mentioned by Hacketo) Regex is regex, they don’t get changed with respect to languages but yes, the way they are tested, changes..You just need to look into how to match a string with a regex in java. 3 solved Convert … Read more
A Map is a key-value pair, i.e., a value is associated to a key. Your code can be refactored as follows: Map<String, Object> details = taskManager.getFormDetails(appSessionURI, accessToken); //System.out.println(“Details :” + details); String fileName = (String)details.get(“fileName”); String refGene = (String)details.get(“refgene”); 3 solved Retrieve value in HashMap [closed]
Something like this should do it: def arr = [] def al = [] for (i in 1..3) { arr = [] arr[0] = 1 //some value arr[1] = 2 //some value al.add(arr) } println al[0][1] 1 solved Arrays and Collection with Groovy [closed]
Use itemStateChanged event to detect the radio button enabled & do your stuff, @Override public void itemStateChanged(ItemEvent e) { if (e.getStateChange() == ItemEvent.SELECTED) { yourButton.enabled=true; } else if (e.getStateChange() == ItemEvent.DESELECTED) { yourButton.enabled=false; } } 1 solved Activating JButton when radio button is enabled? [closed]
It looks like you’ve confused yourself by adding arrays to lists. This effectively gives you another “layer”: You’ve got the list (l or l1), which contains an array, which contains some strings. The problem is you’re thinking of the lists as if they contained strings, when they do not. Let me comment your code to … Read more
Please try below i mentioned date format code,I hope it will help you, From this, String inputDate = “31.12.9999”; SimpleDateFormat dateFormatter = new SimpleDateFormat(“yyyy.MM.dd HH:mm:ss”); Date toDate = dateFormatter.parse(inputDate); To Change: Date date = new SimpleDateFormat(“dd.MM.yyyy”).parse(“31.12.9999”); String formattedDate = new SimpleDateFormat(“yyyy.MM.dd HH:mm:ss”).format(date); System.out.println(“formattedDate :: ” + formattedDate); Thanks,. 2 solved How to format the given … Read more