[Solved] Check if array Is235

Try this, I tested it and it works, you should use the remainder operator %: public class Array { public static void main(String[] args) { int[] arr = {2, 3, 5, 7, 11}; System.out.println(is235Array(arr)); } public static int is235Array(int[] a) { int countOne = 0; int countTwo = 0; for (int i : a) { … Read more

[Solved] What are the Similarities between Dictionary and Array data types? [closed]

A dictionary maps strings to values. An array maps integers to values. That is about it! So, seriously: in the end, both data structures map a “key set” to values. For dictionaries, the keys can of (almost) arbitrary type, without any constraint on them (besides being “hash able”). Whereas an array maps a consecutive range … Read more

[Solved] Java Reconstruct data structure using lambda expression

Does the String in Map<String, List<A>> related to the output? I assume that you want to get every pair <F, E> from the original map right? So this might help Map<String, List<A>> input; input.values().stream() .flatMap(Collection::stream) .map(a -> a.getListB()) // extract list B from A .flatMap(Collection::stream) // Here you get all B instances .collect( toMap( b … Read more

[Solved] Generate a RANDOM id for users [closed]

(You will want to take a look at the Random class in java. It provides random numbers, which is very useful. To answer your question, I would suggest having a String of allowed characters in the ID, and constructing a new string using a StringBuilder, by selecting random characters from your ALLOWED_CHARACTERS string. Something like … Read more

[Solved] i want to retrieve current logged user data from firestore but this show error [duplicate]

Change your onCreate method code to : protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_my_account); email = (TextView)findViewById(R.id.email_txt); mAuth = FirebaseAuth.getInstance(); UserId = mAuth.getCurrentUser().getUid(); passwordtxt = (TextView)findViewById(R.id.pass_txt); mFirestore = FirebaseFirestore.getInstance(); mFirestore.collection(“Hospitals”).document(UserId).get().addOnSuccessListener(new OnSuccessListener<DocumentSnapshot>() { @Override public void onSuccess(DocumentSnapshot documentSnapshot) { String user_name = documentSnapshot.getString(“email”); String password = documentSnapshot.getString(“password”); email.setText(user_name); passwordtxt.setText(password); } }); } 5 solved i want … Read more

[Solved] Cannot verify signature (cmssigneddata) bouncycastle

You need to add the certificate to a org.bouncycastle.util.CollectionStore, and add this store to the signature. I’m using BouncyCastle 1.56: import org.bouncycastle.cert.X509CertificateHolder; import org.bouncycastle.util.CollectionStore; // add these lines after gen.addSignerInfoGenerator(…) // cert is your X509Certificate X509CertificateHolder holder = new X509CertificateHolder(cert.getEncoded()); CollectionStore<X509CertificateHolder> certStore = new CollectionStore<>(Collections.singletonList(holder)); gen.addCertificates(certStore); // add the store to the signature The CollectionStore … Read more

[Solved] Java String comparison wrong outcome [closed]

You should write it like that, way easier to read : if (!Arrays.asList(ip, port, username, password).contains(newSet)) { saveButton.setEnabled(true); } else { saveButton.setEnabled(false); } Or : saveButton.setEnabled(!Arrays.asList(ip, port, username, password).contains(newSet)); 1 solved Java String comparison wrong outcome [closed]

[Solved] SunMSCAPI returns no certificates

You are seeing the computer certificates, not user certificates. Windows-MY keystore only can use the personal user certificates. You can explore the personal certificates using Manage user certificates (certmgr )from control panel instead of Manage computer certificates (certIm) 1 solved SunMSCAPI returns no certificates

[Solved] Return words with characters [a,b,b,c]

Ideally you should try the steps 2 and 3 and come to SO when you are stuck with an issue and you can’t find an answer. For now, I will give you my approach – Just a pseudocode: for(int i=0;i<arr.length;i++) { Map<Character,Integer> temp = hm; for(Character c : arr[i].toCharArray()) { if(!temp.containsKey(c) or temp[c]<=0) break the … Read more