java

[Solved] How to solve ArrayIndexOutOfBoundsException error on trying to print appended object in an array? [duplicate]

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[ad_1] This line System.out.println(ages[1].intValue()); is incorrect. ages is exactly one element. It should be System.out.println(ages[0].intValue()); with no other changes I get tony 50 70 To get 60, you would need to print the second element of oldAge. Like, System.out.println(oldAge[1]); [ad_2] solved How to solve ArrayIndexOutOfBoundsException error on trying to print appended object in an array? … Read more

[Solved] Error passing and getting Array values in Java

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[ad_1] The size of the cost array is 2 but you have declared it of size 1. This will create ArrayIndexOutOfBoundsException. Replace the loop with this single statement so that the return type double[] matches cost_grd= Total_cost(); 1 [ad_2] solved Error passing and getting Array values in Java

[Solved] How do I fix NullPointerException and putting data into NatTable

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[ad_1] Your problem is that you have nested objects and you want to access them via reflection. That is not working! If your Student would only have one exam, you would need to change the propertyNames to this: String[] propertyNames = { “name”, “groupNumber”, “exam.name”, “exam.mark” }; and the definition of the data provider to … Read more

[Solved] Java Program printing infinitely before crashing

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[ad_1] Your DrowRanger method is calling itself infinitely. This is almost always the cause of a StackOverflowException. This line: return DrowRanger(); Calls the DrowRanger method, but since you’re inside the DrowRanger method it just keeps calling itself infinitely. I think you meant to return the local object: return DrowRanger; In general, it is a bad … Read more

[Solved] Running Multiple Thread Pools (ExecutorService) together

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[ad_1] If you need sequential activity, you can call one task and then another. The simple solution in your case is something like this. ExecutorService exec = Executors.newFixedThreadPool(2); exec.execute(new Runnable() { public void run() { userProvisioner1.run(); userProvisioner2.run(); } }); exec.execute(new Runnable() { public void run() { userProvisioner3.run(); userProvisioner4.run(); } }); exec.shutdown(); exec.awaitTermination(); [ad_2] solved Running … Read more

[Solved] java.lang.StackOverflowError when trying to add the same instance of list multiple times

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[ad_1] All your Parent instances have the same list of children, since you construct a single ArrayList and use it as the children of all three Person. So you have a recursive data structure. Create a different list for each person. [ad_2] solved java.lang.StackOverflowError when trying to add the same instance of list multiple times

[Solved] Google Maps Api v2 Android Error

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[ad_1] Because version 2 of the Google Maps Android API requires OpenGL ES version 2, you must add a element as a child of the manifest element in AndroidManifest.xml: <uses-feature android:glEsVersion=”0x00020000″ android:required=”true”/> This notifies external services of the requirement. In particular, it has the effect of preventing Google Play Store from displaying your app on … Read more

[Solved] Relation between class A and class B

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[ad_1] It’s just an nested class i.e. class within class. It’s similar to you defining field and passing value like say private String mystr = new String(str); So here you can access private field str and pass it onto String. Similarly you have defined non static class within the outer class which would access private/protected/public … Read more

[Solved] How to search an Array for a string

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[ad_1] I got your problem. you need to declare the String[] hotel or String[] rooms as the global member. The scope of the String[] hotel would have been gone when the function execution is completed if you are using in another function or in main then it will be a different String array. So only … Read more

[Solved] Searching in folder

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[ad_1] Good one, but it is a more clear to use listFiles(FileFilter filter) public class MyFileFilter implements FileFilter { public boolean accept(File pathname) { if (pathname.isDirectory()) return false; else { String temp[] = pathname.getName().split(“.”); if (temp[1].equals(“a”)) return true; } } } [ad_2] solved Searching in folder